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vfiekz [6]
2 years ago
9

How do halogen react with water?

Chemistry
2 answers:
Finger [1]2 years ago
6 0
It EXPLODES!!!!!!!! and or catches on fire
Ganezh [65]2 years ago
4 0
Well its determined by that iodine and bromine cannot oxidize water to oxygen because they have smaller reduction potentials rather than oxygen. Hope this helps, and if i'm wrong then i understand :)
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Which element would you expect to be more metallic?<br> (a) Ca or Rb (b) Mg or Ra (c) Br or I
svlad2 [7]

Explanation:

When we move across a period from left to right then there will occur an increase in electronegativity and also there will occur an increase in non-metallic character of the elements.

As calcium (Ca) is a group 2A element and rubidium (Rb) is a group 1A element. Hence, Rb being an alkali metal is more metallic in nature than calcium (alkaline earth metal).

Both magnesium (Mg) and radium (Ra) are group 2A elements. And, when we move down a group then as the size of element increases so, it becomes easy of the metal atom to lose an electron.

As a result, there occurs an increase in metallic character of the element. Hence, Radium (Ra) is more metallic in nature than magnesium (Mg).

Also, both bromine and iodine are group 17 elements. Since, both of them are non-metals and non-metallic character increases on moving down the group.

Therefore, bromine (Br) is more metallic than iodine.

7 0
3 years ago
Which of the following are parts of the excretory system? *
Kay [80]

Answer:

kidney, bladder, rectum, urethera

Explanation:

5 0
3 years ago
13. Which statement about trace elements in our atmosphere is false?
tatiyna

Answer: sorry I’m not sure

Odjri:

6 0
2 years ago
Why do elements in a vertical column of the periodic table have similar chemical properties?
iogann1982 [59]

Answer:they have the same number of electrons in the valence shell

Explanation:

3 0
3 years ago
Consider the insoluble compound nickel(II) hydroxide , Ni(OH)2 . The nickel ion also forms a complex with cyanide ions . Write a
natali 33 [55]

Answer: Equilibrium constant for this reaction is 2.8 \times 10^{15}.

Explanation:

Chemical reaction equation for the formation of nickel cyanide complex is as follows.

Ni(OH)_{2}(s) + 4CN^{-}(aq) \rightleftharpoons [Ni(CN)_{4}^{2-}](aq) + 2OH^{-}(aq)

We know that,

      K = K_{f} \times K_{sp}

We are given that, K_{f} = 1.0 \times 10^{31}

and,    K_{sp} = 2.8 \times 10^{-16}

Hence, we will calculate the value of K as follows.

     K = K_{f} \times K_{sp}

     K = (1.0 \times 10^{31}) \times (2.8 \times 10^{-16})

        = 2.8 \times 10^{15}

Thus, we can conclude that equilibrium constant for this reaction is 2.8 \times 10^{15}.

4 0
2 years ago
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