Whatisthechemicalequationforthereactionofaqueoussodiumhydroxidewithaqueoushydrochloricacid

Suppose that 0.25 mole of gas C was added to the mixture without changing the total pressure of the mixture. How does the additi

Yanka [14]

Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.

On addition of 0.25 moles of C gas, the mole fraction of gas A will be $\frac{moles of gas A}{moles of gas A + 0.25}$ .

The partial pressure of gas A can be written as $P_{A}$ = $x_{A}$ ×P (where $x_{A}$ is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.

The mole fraction of gas A in a mixture of gas A and C is = $\frac{moles of gas A}{moles of gas A + moles of gas C}$ and $\frac{moles of gas C}{moles of gas A + moles of gas C}$ respectively.

Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be $\frac{moles of gas A}{moles of gas A + 0.25}$ .

Which is different from the initial state.

4 0

3 years ago

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A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

Answer: The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

Explanation:

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

4 0

3 years ago

What statement best describes solution

kirza4 [7]

Solution is a mixture of solvent and solute. Which dissove completely.

Examples of Solvent - Water

Solute - Salt

Solution - Salt solution

Together when the combines, it became a solution

*** It have to dissolve completely. Particles cannot be left in the cup(container). The only way to seprate them is to use EVAPORATION METHOD.

6 0

4 years ago

Question 1 (1 point)

Anastaziya [24]

Answer: 2

Explanation: 2Li + 2H2O → 2LiOH + H2

***If you found my answer helpful, please give me the brainliest. :) ***

3 0

3 years ago

When you apply heat energy to a substance, where does the energy go? Think about the law of conservation of energy.

Softa [21]

Answer:

the heat energy is transformed to any kind of energy depending on what it's meant to be transformed to.

remember it cannot be destroyed so it's definitely transformed to some kinda energy

8 0

3 years ago

Whatisthechemicalequationforthereactionofaqueoussodiumhydroxidewithaqueoushydrochloricacid​

Whatisthechemicalequationforthereactionofaqueoussodiumhydroxidewithaqueoushydrochloricacid