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Ostrovityanka [42]
4 years ago
7

HELP Define the Gravitational field strength of earth

Physics
1 answer:
Contact [7]4 years ago
7 0

Answer:

The gravitation field strength of earth can be written as 9.8 N/Kg or 10 N/Kg. This means that an object with a mass of 1kg will be attracted towards the centre of Earth by a force of 9.8 N/kg or 10 N/kg

Explanation:

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A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball
jonny [76]

(a) The impulse delivered to the ball by the racket is 5.24 kg.m/s

(b) The work that the racket does on the ball is -35.1 Joule

<h3>Further Explanation</h3>

<u>Given :</u>

mass of ball = m = 0.06 kg

initial velocity = v₁ = -50.4 m/s

final velocity = v₂ = 37.0 m/s

<u>Unknown :</u>

(a) Impulse = I = ?

(b) Work = W = ?

<u>Solution :</u>

<h2>Question (a) :</h2>

In this question , we could use the formula from Second Law of Newton :

I = \Delta p

I = p_2 - p_1

I = m \times v_2 - m \times v_1

I = m \times (v_2 - v_1)

I = 0.06 \times (37.0 - (-50.4))

I = 0.06 \times (87.4)

I = 5.244~kg.m/s

\large { \boxed {I \approx 5.24~kg.m/s} }

<h2>Question (b) :</h2>

W = F \times d

W = (\frac{I}{\Delta t})(\frac {v_1 + v_2}{2} \Delta t)

W = \frac{I(v_1 + v_2)}{2}

W = \frac{5.244(-50.4 + 37)}{2}

W = \frac{5.244(-13.4)}{2}

W = -35.1348~Joule

\large { \boxed {W \approx -35.1~Joule}}

<h3>Learn more</h3>

Newton's Law of Motion: brainly.com/question/10431582

Example of Newton's Law: brainly.com/question/498822

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Newton, Law, Impulse, Work

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4 years ago
How do throns Mostly likely help a plant to survive
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Thorns protect plants from insects or harmful bugs.
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While using a digital radiography system, suppose a radiographer uses exposure factors of 10 mAs and 70 kVp with an 8:1 grid for
Nimfa-mama [501]

Answer:

b. 12.5 mAs, 70 kVp

Explanation:

The given parameter are;

The initial exposure factors := 10 mAs and 70 kVp

The initial Grid Ratio, G.R.₁ = 8:1

The Grid Ratio with which the radiographer desires to increase the scatter absorption, G.R.₂  = 12:1

Given that the lead content in the 12:1 grid, is higher than the lead content in 8:1 grid and that 12:1 grid needs more mAs to compensate, and provides a higher image contrast, the amount of extra mAs is given by the Grid Conversion Factors, GCF, as follows;

The GCF for G.R. 8:1 = 4

The GCF for G.R. 12:1 = 5

Therefore, given that the mAs used by the radiographer for 8:1 Grid Ratio is 10 mAs, the mAs required for a G.R. of 12:1 in order to maintain the same exposure is given as follows;

mAs for G.R. of 12:1 = 10 mAs × 5/4 = 12.5 mAs

Therefore the new exposure factors are;

12.5 mAs, 70 kVp

5 0
3 years ago
How does food affects carbon footprint?
eduard

Answer:

Food accounts for 10-30% of a household's carbon footprint, typically a higher portion in lower-income households. Production accounts for 68% of food emissions, while transportation accounts for 5%.

Explanation:

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