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inysia [295]
2 years ago
12

Which of these best describes the relationship between the incident ray, the reflected ray, and the normal for a curved mirror?(

1 point)
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.

The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.

The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.

The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
Physics
1 answer:
lions [1.4K]2 years ago
8 0

For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.

According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.

Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.

Learn more: brainly.com/question/17638582

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8 0
3 years ago
A man starts walking north at 3 ft/s from a point P. Five minutes later a woman starts walking south at 4 ft/s from a point 500
mrs_skeptik [129]

Answer:

ds/dt = 6.98 ft/s

Explanation:

Given:

- The speed of man due north Vm = 3 ft/s

- The speed of woman due south Vw = 4 ft/s

- Woman starts walking 5 mins later than man

Find:

At what rate are the people moving apart 15 min after the woman starts walking?

Solution:

- The total time for which the man is walking due north from P, is Tm:

                                   Tm = 5 + 15 = 20 mins

- The total distance traveled by man in Tm mins is:

                                   Dm = Tm*Vm

                                   Dm = 20*60*3

                                   Dm = 3,600 ft

- The total time for which the woman is walking due south from 500 ft due east from P, is Tw:

                                   Tw = 15 = 15 mins

- The total distance traveled by man in Tw mins is:

                                   Dw = Tw*Vw

                                   Dw = 15*60*4

                                   Dw = 3,600 ft

- The displacement between man and woman at any instance is (s) which can be related by pythagoras theorem as follows:

                                   s^2 = (dm + dw)^2 + 500^2

Where, dm : Distance travelled by man at any time Tm

            dw : Distance travelled by woman at any time Tw

- Differentiate s with respect to t:

                                   2s*ds/dt = 2*(dm + dw)*(Vm + Vw)

                                   s*ds/dt = (dm + dw)*(Vm + Vw)

                                   ds/dt = [ (dm + dw)*(Vm + Vw) ] / s

- Evaluate the rate of separation of man and woman ds/dt by evaluating at instance Tm = 20 mins and Tw = 15 mins. We have:

                 ds/dt = [ (Dm + Dw)*(Vm + Vw) ] / sqrt ( (Dm + Dw)^2 + 500^2 )

- Plug in the values:

                 ds/dt = [ (3600 + 3600)*(3 + 4) ] / [sqrt ( (3600 + 3600)^2 + 500^2 )]  

                ds/dt = 6.98 ft/s

                 

           

7 0
3 years ago
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