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inysia [295]
2 years ago
12

Which of these best describes the relationship between the incident ray, the reflected ray, and the normal for a curved mirror?(

1 point)
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.

The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.

The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.

The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
Physics
1 answer:
lions [1.4K]2 years ago
8 0

For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.

According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.

Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.

Learn more: brainly.com/question/17638582

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Answer:

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Explanation:

Given that,

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Using formula of current

i=\dfrac{V_{0}}{R}e^{\frac{-t}{RC}}

Put the value into the formula

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\dfrac{-t}{RC}=ln(0.600)

t=0.51\times1.8\times10^{3}\times120\times10^{-6}

t=110.16\times10^{-3}\ sec

Hence, The time is 110.16\times10^{-3}\ sec

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