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Anarel [89]
2 years ago
9

A body of mass 100kg exerts pressure of 50.000N\M².calculate the area over which the force acts​

Physics
2 answers:
yanalaym [24]2 years ago
6 0

Answer:

the area is 0.0196 m^2

Explanation:

Recall that pressure is defined as the force over the surface area:

Pressure = Force / Area

Therefore, Area =  Force / Pressure

in our case, the acting force is the gravitational force Fg = m * g = 100 * 9.8 N = 980 N

and the pressure is 50000 N/m^2

Then the acting area is:

980 / 50000 m^2 = 0.0196 m^2

hoa [83]2 years ago
4 0
The area is 0.0196m^2
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zubka84 [21]

50m

Explanation:

Displacement is the length of path traveled which is measured from start to the finishing of the path.

    Analysis of the journey;

 Starts from:

 0                                    30m                                              from right

                  15m                                                                       to left

                                                                       50m              to right

                 

The displacement is 50m from the starting point.

Distance is total path traveled and for this problem it is 30+ 15 + 50 = 95m

learn more:

displacement brainly.com/question/5461768

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8 0
2 years ago
A flow is isentropically expanded to supersonic speeds in a convergent-divergent nozzle. The reservoir and exit pressures are 1.
Kamila [148]

Answer:

Ae/A* = 1.115

Explanation:

Let the reservoir pressure be  p_0

Let the exit  pressure be p_e

Ratio of reservoir pressure and exit pressure

\frac{p_o}{p_e} = \frac{1}{0.3143}

  = 3.182

For the above value of pressure ratio

Obtain the area ratio from the isentropic flow table

Ae/A* = 1.115

The value of pressure ratio is Ae/A* = 1.115

6 0
2 years ago
Enunciado: Una bola se lanza verticalmente de la parte superior de un edificio con una velocidad inicial de 25 m/s. La bola impa
bearhunter [10]

Responder:

Explicación:

Usaremos la ecuación de movimiento para determinar la altura de la bola medida desde la parte superior del edificio.

Usando la ecuación para obtener la altura de caída

S = ut + 1 / 2gt²

u es la velocidad inicial = 25 m / s

g es la aceleración debida a la gravedad = 9,81 m / s²

t es el tiempo = 7 segundos

S es la altura de la caída

S = 25 (7) +1/2 (9,81) × 7²

S = 175 + 4,905 (49)

S = 175 + 240,345

S = 415,35 m

Esto significa que la pelota se elevó a 415,35 m de altura

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3 years ago
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