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3 years ago

A body of mass 100kg exerts pressure of 50.000N\M².calculate the area over which the force acts

Physics

2 answers:

yanalaym [24]3 years ago

6 0

Answer:

the area is 0.0196 m^2

Explanation:

Recall that pressure is defined as the force over the surface area:

Pressure = Force / Area

Therefore, Area = Force / Pressure

in our case, the acting force is the gravitational force Fg = m * g = 100 * 9.8 N = 980 N

and the pressure is 50000 N/m^2

Then the acting area is:

980 / 50000 m^2 = 0.0196 m^2

hoa [83]3 years ago

4 0

The area is 0.0196m^2

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3 years ago

A Ferris wheel starts at rest and builds up to a final angular speed of 0.70 rad/s while rotating through an angular displacemen

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Answer:

The average angular acceleration is 0.05 radians per square second.

Explanation:

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$\omega^{2} = \omega_{o}^{2} + 2 \cdot \alpha\cdot (\theta-\theta_{o})$

Where:

$\omega_{o}$ , $\omega$ - Initial and final angular velocities, measured in radians per second.

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$\theta_{o}$ , $\theta$ - Initial and final angular position, measured in radians.

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$\alpha = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot (\theta-\theta_{o})}$

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$\alpha = \frac{\left(0.70\,\frac{rad}{s} \right)^{2}-\left(0\,\frac{rad}{s} \right)^{2}}{2\cdot \left(4.9\,rad\right)}$

$\alpha = 0.05\,\frac{rad}{s^{2}}$

Now, the time needed to accelerate the Ferris wheel uniformly is described by this kinematic equation:

$\omega = \omega_{o} + \alpha \cdot t$

Where $t$ is the time measured in seconds.

The time is cleared and obtain after replacing every value:

$t = \frac{\omega-\omega_{o}}{\alpha}$

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$t = \frac{0.70\,\frac{rad}{s} - 0\,\frac{rad}{s} }{0.05\,\frac{rad}{s^{2}} }$

$t = 14\,s$

Average angular acceleration is obtained by dividing the difference between final and initial angular velocities by the time found in the previous step. That is:

$\bar \alpha = \frac{\omega-\omega_{o}}{t}$

If $\omega_{o} = 0\,\frac{rad}{s}$ , $\omega = 0.70\,\frac{rad}{s}$ and $t = 14\,s$ , the average angular acceleration is:

$\bar \alpha = \frac{0.70\,\frac{rad}{s} - 0\,\frac{rad}{s} }{14\,s}$

$\bar \alpha = 0.05\,\frac{rad}{s^{2}}$

The average angular acceleration is 0.05 radians per square second.

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3 years ago

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Put the value into the formula

$n=\dfrac{16}{2}$

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Read 2 more answers

A body of mass 100kg exerts pressure of 50.000N\M².calculate the area over which the force acts​

A body of mass 100kg exerts pressure of 50.000N\M².calculate the area over which the force acts