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3 years ago

In your own words, define the following terms. Radiation, Convection, and conduction.

Physics

1 answer:

Dafna11 [192]3 years ago

3 0

Radiation: transferred energy
Convection: Transfer of heat
Conduction: transfer of electric charge

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An electron is moving in the presence of an electric field of 400 N/C. What force does the electron experience?

yanalaym [24]

Answer:

Explanation:

Given

Electric Field strength $E=400\ N/C$

charge of electron $q=1.6\times 10^{-19}\ C$

Force on the charge particle is given by

$F=qE$

$F=1.6\times 10^{-19}\times 400$

$F=640\times 10^{-19}\ N$

but this force will be acting in the direction opposite to the direction of Electric field because electron is negatively charged

8 0

3 years ago

A river is flowing south at a rate of 3 m/s. Steven can roe directly across the river if he aims the raft 30 degrees. What rate

levacccp [35]

Answer:

Steven has to row at a speed to reach the same horizontal spot at the other side of the river is, V = 6 m/s

Explanation:

Given data,

The river flowing south at the rate, v = 3 m/s

To reach the other side directly across the river, he aims the raft, Ф = 30°

The speed of his raft across the river is given by the formula,

V = v / Sin Ф

= 3 / Sin 30°

= 6 m/s

Steven has to row at a speed to reach the same horizontal spot at the other side of the river is, V = 6 m/s

3 0

3 years ago

g You drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 k

Salsk061 [2.6K]

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

$2gh = v_f^2 - v_i^2\\$

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

$(2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s$

Now, we will apply the law of conservation of momentum:

$m_1v_1 = m_2v_2$

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

$(3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s$

Now, we again use the third equation of motion for the upward motion of the ball:

$2gh = v_f^2 - v_i^2\\$

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

$(2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\$

6 0

3 years ago

What does it mean to say that in any system the total energy score stays the<br> same

timurjin [86]

Answer:

energy is conserved

a force sets an object in motion. when the force is multiplied by the time of its application we call the quantity impulse which changes the momentum of that object. what do we call the quantity force x (times) distance, and what quantity can this change?

7 0

4 years ago

A simple pendulum with length L is swinging freely with

Trava [24]

Answer:

it will be 1/√2 of its original period.

Explanation:

8 0

3 years ago