Hello, for this use the <u>2nd law of Newton:</u>
F = ma
Replacing:
4200 N = m * 60 m/s^2
Resolving:
4200 N / 60 m/s^2 = m
70 kg = m
The mass is <u>70 kg</u>
Answer:
Formula: Remove the zero from the speed, multiply the figure by itself and then multiply by 0.4. The figure 0.4 is taken from the fact that the braking distance from 10 km/h in dry road conditions is approximately 0.4 metres.
Answer:
New volume (V2) = 60 liter
Explanation:
Given:
Amount of helium (V1) = 20 Liter
Temperature (T1) = 100°K
Temperature (T2) = 300°K
Find:
New volume (V2)
Computation:
According to Gas Law:
V1 / T1 = V2 / T2
20 / 100°K = V2 / 300°K
V2 = 60 liter
New volume (V2) = 60 liter
Answer:
a ) 
b) 
Explanation:
given data:
pressure ration rp = 12
inlet temperature = 300 K
TURBINE inlet temperature = 1000 K
AT the end of isentropic process (compression) temperature is



AT the end of isentropic process (expansion) temperature is



isentropic work is given as

w = 1.005(610.18 - 300)
w = 311.73 kJ/kg
w(turbine) = 1.005( 1000 - 491.66)
w(turbine) = 510.88 kJ/kg
a) mass flow rate for isentropic process is given as


b) actual mass flow rate uis given as


Answer : 
Explanation :
It is given that,
Mass of the engine, m = 30 kg
Thrust is equivalent to the force acting perpendicularly and it is F = 300 N
According to Newton's second law of motion :

a is the acceleration of the engine.



So, the acceleration of the engine is
.
Hence, this is the required solution.