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4 years ago

15

A player kicks a soccer ball from ground level and sons at flying at an angle of 30° at a speed of 26MS how far did the ball tra

vel before it hit the ground round the answer to the nearest meter

1 answer:

RSB [31]4 years ago

7 0

Answer:

Explanation:

60 meters is he answer for this question

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At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constan

liubo4ka [24]

Answer:

a) t = 11.407 s, b) x = 175.66 m, v = c) v = 30.80 m / s

Explanation:

a) This is a kinematics exercise, let's write the equation of each vehicle

car

x = x₀ + v₀ t + ½ a t²

Let's fix our reference system at the point where the car is, indicate that the car stops from rest vo = 0

x₀ = v₀ = 0

we substitute

x = ½ a t²

truck

x₂= v₀ t

v₀ = 15.4 m / s

at the point where they are, their positions are equal

½ a t² = vo t

t = 2 vo / a

calculate us

t = 2 15.4 / 2.70

t = 11.407 s

b) the distance to reach it

x = ½ to t²

x = ½ 2.70 11.407²

x = 175.66 m

c) the speed of the car is

v = vo + a t

vo = 0

v = at

v = 2.70 11.407

v = 30.80 m / s

4 0

3 years ago

Ways that charges can be transferred

Rama09 [41]

Can I have more Details?

8 0

3 years ago

Read 2 more answers

I need help with this physics question, "A skateboarder rolled down the sidewalk with an initial velocity of 2.5m/s. If her acce

scoray [572]

Recall that

${v_f}^2={v_i}^2+2a\Delta x$

where $v_i$ and $v_f$ are the skateboarder's velocity, respectively; $a$ is her acceleration; and $\Delta x$ is the change in her position.

Substitute everything you know and solve for $v_f$ :

${v_f}^2=\left(2.5\dfrac{\rm m}{\rm s}\right)^2+2\left(1.7\dfrac{\rm m}{\mathrm s^2}\right)(130\,\mathrm m)\implies v_f=448.25\dfrac{\mathrm m^2}{\mathrm s^2}\implies\boxed{v_f\approx21\dfrac{\rm m}{\rm s}}$

5 0

4 years ago

Consider an aircraft with a finite wing area of 60.0 m2 and an aspect ratio of 8. Assume the wing is composed of a NACA 65-210 a

kaheart [24]

Answer:

CL = 0.57

CD = 0.027

Explanation:

Thinking process:

Let the parameters be:

wing area = 21.5 m²

aspect ratio = 5

span efficiency factor = 0.9

CD₀ = 0.004

Angle AOA = 6°

Therefore,

$CD = CD_{0} + \frac{(CL)^{2} }{ITEAR}$

For the NACA 65210

α = 9° ; CL = 1.05

α = -1.5 ; Cl = 0

Therefore, $a_{0} = \frac{1.05- 0}{9-(-1.5)} \\ = 0.11$

Lift slope for finite wing is given by:

$a = \frac{a_{0} }{1+\frac{a_{0} }{ITEAR} } \\ = \frac{0.11}{1+\frac{57.3(0.11)}{\pi }(0.9)(5) }\\ = 0.076 deg$

at α = 6°, CL is given by:

a ( $\alpha -\alpha _{L=0}) = 0.076(6-(-1.5)\\ CL= 0.57$

CD = $0.004 + \frac{(0.57)^{2} }{\pi*0.9*6 }$

= 0.027

6 0

4 years ago

The movement of electrons through a wire is called.....

Elenna [48]

Answer:

Electric Current

Explanation:

5 0

3 years ago

Read 2 more answers