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2 years ago

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1

="1 \div {3}^{ - 2} " align="absmiddle" class="latex-formula">

2 answers:

True [87]2 years ago

8 0

Answer:

$1 \div {3}^{ - 2}$

$1 \div \frac{1}{ {3}^{2} }$

By doing reciprocal we get

$1 \times {3}^{2}$

$9$

notka56 [123]2 years ago

4 0

Answer:

9.

Step-by-step explanation:

1 / 3^-2

= 1 / 1/3^2

= 1 * 3^2

= 9.

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2 years ago

Four times a number times three is the same as five plus the number; is the equation

AVprozaik [17]

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3 years ago

Read 2 more answers

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3 years ago

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Step-by-step explanation:

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3 years ago

If the point (a, b) is equidistant from the points (-a, 2) and (2, -b), then prove that 3(a+b)+4=0

erastova [34]

Answer: see proof below

<u>Step-by-step explanation:</u>

Since (a, b) is equidistant from (-a, 2) and (2, -b), then it is the midpoint of the those two points. Use Midpoint formula to find (a, b).

$M_x=\dfrac{x_1+x_2}{2}\qquad \qquad \qquad M_y=\dfrac{y_1+y_2}{2}\\\\\\a=\dfrac{-a+2}{2}\qquad \qquad \qquad \quad b=\dfrac{2-b}{2}\\\\\\2a=-a+2\qquad \qquad \qquad \quad 2b=2-b\\\\\\3a=2\qquad \qquad \qquad \qquad \qquad 3b=2\\\\\\a=\dfrac{2}{3}\qquad \qquad \qquad \qquad \qquad b=\dfrac{2}{3}$

3(a + b) - 4 = 0

$3\bigg(\dfrac{2}{3}+\dfrac{2}{3}\bigg)-4=0\\\\\\3\bigg(\dfrac{4}{3}\bigg)-4=0\\\\\\4-4=0\\\\0=0\qquad \text{TRUE!}$

<em>Notice that I changed the equation to "negative 4" because the equation you provided did not make a true statement.</em>

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3 years ago