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Citrus2011 [14]
3 years ago
10

A chemical reaction was used to produce 2.54 moles of copper(II) bicarbonate, Cu(HCO3)2. What mass of copper(II) bicarbonate was

produced?
Chemistry
1 answer:
emmainna [20.7K]3 years ago
5 0

Answer:

The answer to your question is 471.2 g

Explanation:

Data

moles of Cu(HCO₃)₂ = 2.54

mass of Cu(HCO₃)₂ = ?

Process

1.- Calculate the molar mass of Copper (II) bicarbonate

Cu(HCO₃)₂ = (1 x 63.5) + (2 x 1) + (2 x 12) + (6 x 16)

                  = 63.5 + 2 + 24 + 96

                  = 185.5 g

2.- Use proportions and cross multiplication to find the mass

                     185.5 g of Cu(HCO₃)₂ ------------- 1 mol

                         x                               ------------- 2.54 mol

                                   x = (2.54 x 185.5) / 1

                                   x = 471.2 g

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if three oxygen particles are needed to form ozone, how many units of ozone could be formed from 6 oxygen particles? from 9? fro
tensa zangetsu [6.8K]
<h3>Answers:</h3>

             1) 2 Units of Ozone

             2)  3 Units of Ozone

              3)  9 Units of Ozone

<h3>Solution:</h3>

1)  From 6 Oxygen Particles;

As given,

                          3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      6 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (6 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  2 Units of Ozone

2) From 9 Oxygen Particles;

As given,

                           3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      9 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (9 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  3 Units of Ozone

3)  From 27 Oxygen Particles;

As given,

                             3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      27 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (27 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  9 Units of Ozone

3 0
3 years ago
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Answer:

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b. Hydrocarbons are hydrophobic.

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As we know that the hydrocarbons is a mix of carbon and hydrogen. In this the availability of the electronegative atom is not there that shows there is no bonding of the hydrogen plus it is dissolved. Also, the hydrocarbons is considered to be a non-polar but as compared to the water, water is a polar

In addition to this, the strong bond is no existed that shows the lower boiling points  

Therefore option A, B and D are right

8 0
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