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agasfer [191]
3 years ago
7

Individual particles move with the wave.

Chemistry
1 answer:
MArishka [77]3 years ago
3 0

Answer:

No.

Explanation:

No, individual particles do not move with the wave, it only oscillates back and forth its mean position. The particles in the medium transfer its energy to their neighboring particles and in that way the energy moves in the form of wave. The particles only vibrates on its means position instead of moving from one place to another. So we can conclude that Individual particles do not move with the wave.

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3 years ago
What group of elements generally have the lowest second ionization energy?
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3 years ago
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A 200 g of sugar was dissolved in 100 ml of water describe the solution
yarga [219]

Answer:

b

Explanation:

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7 0
2 years ago
Determine Δngas for each of the following reaction:(b) 2PbO(s) + O₂(g) ⇄ 2PbO₂(s)
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Then Δngas = -1

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about Equilibrium

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1 year ago
An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar
Karolina [17]

Explanation:

First, we will calculate fuel consumption is as follows.

         372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s

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Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

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Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is 1.19 \times 10^{5} kW.

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