Answer:
The percent abundance of oxygen-18 is 1.9066%.
Explanation:
The average atomic mass of oxygen is given by:
Where:
m: is the atomic mass
%: is the percent abundance
Since the sum of the percent abundance of oxygen isotopes must be equal to 1, we have:
Hence, the percent abundance of O-18 is:
Hence, the percent abundance of oxygen-18 is:
Therefore, the percent abundance of oxygen-18 is 1.9066%.
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Explanation:
a)phenotype= 100% big
b) genotype=1:2:1 (FF-25%, Ff-50%, ff-25%)
phenotype=3:1 (big=75%, small= 25%)
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Answer:
B, D, E, C, A
Explanation:
We have 5 blocks with their respective masses and volumes.
Block Mass Volume
A 65.14 kg 103.38 L
B 0.64 kg 100.64 L
C 4.08 kg 104.08 L
D 3.10 kg 103.10 L
E 3.53 kg 101.00 L
The density (ρ) is an intensive property resulting from dividing the mass (m) by the volume (V), that is, ρ = m / V
ρA = 65.14 kg / 103.38 L = 0.6301 kg/L
ρB = 0.64 kg / 100.64 L = 0.0064 kg/L
ρC = 4.08 kg / 104.08 L = 0.0392 kg/L
ρD = 3.10 kg / 103.10 L = 0.0301 kg/L
ρE = 3.53 kg / 101.00 L = 0.0350 kg/L
The order from least dense to most dense is B, D, E, C, A
Potassium hydroxide (KOH) is formed when Potassium forms ionic bonds with OH-ions while Potassium Oxide (K2O) is formed when potassium forms ionic bonds with the Oxide (O2-) ions. i.e. This reaction is a neutralization reaction and occurs when an acid (HCl) reacts with a base (KOH).
