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zaharov [31]
3 years ago
6

The process of a liquid becoming a gas is call what

Physics
1 answer:
Sergio039 [100]3 years ago
6 0
Vaporization of a sample of liquid is a phase transition from the liquid phase to the gas phase.

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In which situation are both the speed and velocity of the car changing?
lubasha [3.4K]
Answer is A because the speed and velocity would change. Think of it as GTA, your going 30+ miles per hour and you take a left turn, the speed and velocity would change in an instant.. 
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What is the term that describes waves that require a medium through which to travel?
gladu [14]

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

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2 years ago
What life process requires specialized cells in multicellular organisms
worty [1.4K]
The most probable answer for this question would be that almost every life process requires specialized cells in multicellular organisms. To simply put it, cells of multicellular organisms are specialized in a way that they are all grouped into their respective tissues and these tissues are all grouped into their respective organs and these organs are all grouped together into their respective systems and these systems make up the multicellular organisms. These systems have their own functions in maintaining and sustaining the life that the organisms has. The organs have their own functions as well, thus specialized cells are mostly needed in respiration, digestion, circulation, movement, excretion, reproduction, immunity, coordination, and synthesis.
4 0
3 years ago
A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p
kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2

V(t) = V_0 + a * t,

Where y_0 its our initial height, V_0  our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

y(t) =  38 \frac{m}{s} * t - \frac{1}{2} g t^2

V(t) = 38 \frac{m}{s} - g * t

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

0 m = 38 \frac{m}{s} - g * t

and obtain:

t = 38 \frac{m}{s} / g

t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}

t = 3.9 s

Plugin this time on our first equation we find:

y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2

y=73.67 m

6 0
3 years ago
Please help on Problem 2.5 <br><br> I also need a short (or detailed) explanation. Thank you !!
NNADVOKAT [17]

Explanation:

Problem 2.5, mixing dough.

Please note dimensional units and standard formulas for energies.

Input:

Electrical energy = VIT = 110 V * 1.5 A * 5 min. * 60 s/min = 49500 joules = 49.5 kJ

Output:

Warming of dough = mCΔT = 1 kg  * 4.2 kJ/(kg*K) * 5 deg.K = 21 kJ

Dissipation of energy = remainder of input energy = (49.5-21) kJ = 28.5 kJ

Fraction of energy converted to energy of dough = 21 kJ / 49.5 kJ

= forty-two percent (to the nearest percent)

The last item, dissipation of energy could be attributed to:

1. Loss in efficiency of mixer in the form of mechanical friction, heating up due to resistance of motor circuit, etc.

2. Loss in mechanical mixing of dough due to friction between mixer paddle and dough in the form of heat, part of which stays with dough (thus heating up of dough), and the remainder heats up the dough container, loss of heat to environment, air, heat of vaporization of water content of dough, etc.

8 0
3 years ago
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