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2 years ago

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A light ray travels in the +x direction and strikes a slanted surface with an angle of 62° between its normal and the ty axis. T

he surface is a clear solid with an index of refraction 1.33. What is the x component of the direction of the resulting reflected light ray?

1 answer:

Elena-2011 [213]2 years ago

6 0

Answer:

- 0.6

Explanation:

Given that angle between normal y axis is 62° so angle between normal

and x axis will be 90- 62 = 28 °. Since incident ray is along x axis , 28 ° will be the angle between incident ray and normal ie it will be angle of incidence

Angle of incidence = 28 °

angle of reflection = 28°

Angle between incident ray and reflected ray = 28 + 28 = 56 °

Angle between x axis and reflected ray = 56 °

x component of reflected ray

= - cos 56 ( it will be towards - ve x axis. )

- 0.6

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Answer:

Explanation:

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Therefore,

$Gm_1m_2[\frac{1}{r_f} -\frac{1}{r_1} ]=\frac{1}{2} (m_1v_1^2+m_2v_2^2)$

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Substitute the values in the above result

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$x_1=3.962x_2$

and

$x_2=0.252x_1$

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2 years ago

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umka21 [38]

Answer:

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Explanation:

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