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3 years ago

What energy transformations take place when you eat a taco and then go for a jog

Physics

1 answer:

sesenic [268]3 years ago

6 0

Answer:

Chemical to kinetic and thermal.

Explanation:

You would eat the food (chemical) than you would jog and move around (kinetic). While running your body would also give off heat (thermal).Than your body would sweat to cool itself down.

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A scientist discovered an elementary particle paired with another particle. It has a positive charge equal to two–thirds of the

julia-pushkina [17]

W boson has +1e or - 1e charge, Z boson has 0 charge.

Leptons have +1e, -1e or 0 charge.

Photons have 0 charge.

Only quarks have a charge of +2/3e or -1/3e of an electron charge.

To be exact, only up-type quarks (Up, Down and Top quarks) have a +2/3e or two thirds of an electron charge.

So the correct answer is D) Quark.

6 0

3 years ago

A golfer imparts a speed of 30.3 m/s to a ball, and it travels the maximum possible distance before landing on the green. the te

sergey [27]

<u>Answer:</u>

a) Time spend by ball in air = 4.368 seconds

b) Longest hole that golfer can make = 93.59 meter

<u>Explanation:</u>

Projectile motion has two types of motion Horizontal and Vertical motion.

Vertical motion:

We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

Considering upward vertical motion of projectile.

In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g $m/s^2$ and final velocity = 0 m/s.

0 = u sin θ - gt

t = u sin θ/g

Total time for vertical motion is two times time taken for upward vertical motion of projectile.

So total travel time of projectile = 2u sin θ/g

Horizontal motion:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case Initial velocity = horizontal component of velocity = u cos θ, acceleration = 0 $m/s^2$ and time taken = 2u sin θ /g

So range of projectile, $R=ucos\theta*\frac{2u sin\theta}{g} = \frac{u^2sin2\theta}{g}$

a) We have golf ball travels maximum distance, so range is maximum.

Maximum range is when, sin 2θ =1

=> θ = 45⁰

Now we have travel time of projectile, t = 2u sin θ/g

Initial velocity = 30.3 m/s and θ = 45⁰

So time spend in air, t = $\frac{2*30.3*sin45}{9.81} =4.368 seconds$

b) Longest hole that golfer can make = Range of projectile = $\frac{u^2sin2\theta}{g}$

Longest hole that golfer can make = $\frac{30.3^2sin(2*45)}{9.81}=93.59 meter$

4 0

3 years ago

A transformer connected to a 120-v(rms) at line is to supply 13,000V(rms) for a neon sign.

lyudmila [28]

Answer:

(a) 108

(b) 110.500 kW

Solution:

As per the question:

Voltage at primary, $V_{p} = 120\ V$ (rms voltage)

Voltage at secondary, $V_{s} = 13000\ V$ (rms voltage)

Current in the secondary, $I_{s} = 8.50\ mA$

Now,

(a) The ratio of secondary to primary turns is given by the relation:

$\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{s}}$

where

$N_{p}$ = No. of turns in primary

$N_{s}$ = No. of turns in secondary

$\frac{N_{s}}{N_{p}} = \frac{13000}{120}$ ≈ 108

(b) The power supplied to the line is given by:

Power, P = $V_{s}I_{s} = 13000\times 8.50 = 110.500\ kW$

$\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}$

$\frac{13000}{120} = \frac{I_{p}}{8.50}$

$I_{p} = \frac{13000}{120}\times 8.50 = 920.84\ A$

6 0

3 years ago

How much force is required to accelerate a 5 kg object at 5 m/s^2?

kramer

Answer:25n

Explanation:

3 0

3 years ago

Describe how radio telescopes function.

FrozenT [24]

A radio telescope is simply a telescope that is designed to receive radio waves from space. In its simplest form it has three components:

1. One or more antennas to collect the incoming radio waves. Most antennas are parabolic dishes that reflect the radio waves to a receiver, in the same way as a curved mirror can focus visible light to a point.

2. A receiver and amplifier to boost the very weak radio signal to a measurable level. These days the amplifiers are extremely sensitive and are normally cooled to very low temperatures to minimise interference due to the noise generated by the movement of the atoms in the metal (called thermal noise).

3. A recorder to keep a record of the signal. Most radio telescopes nowadays record directly to some form of computer memory disk as astronomers use sophisticated software to process and analyse the data.

7 0

3 years ago