Answer:
362.41 km/h
Explanation:
F = Force
m = Mass = 84 kg
g = Acceleration due to gravity = 9.81 m/s²
C = Drag coefficient = 0.8
ρ = Density of air = 1.21 kg/m³
A = Surface area = 0.04 m²
v = Terminal velocity
F = ma
Converting to km/h
The terminal velocity of the stone is 362.41 km/h
Answer: Mass of the object is 75 kg.
Answer:
a₁ = 0.63 m/s² (East)
a₂ = -1.18 m/s² (West)
Explanation:
m₁ = 95 Kg
m₂ = 51 Kg
F = 60 N
a₁ = ?
a₂ = ?
To get the acceleration (magnitude and direction) of the man we apply
∑Fx = m*a (⇒)
F = m₁*a₁ ⇒ 60 N = 95 Kg*a₁
⇒ a₁ = (60N / 95Kg) = 0.63 m/s² (⇒) East
To get the acceleration (magnitude and direction) of the woman we apply
∑Fx = m*a (⇒)
F = -m₂*a₂ ⇒ 60 N = -51 Kg*a₂
⇒ a₂ = (60N / 51Kg) = -1.18 m/s² (West)
For every case we apply Newton’s 3
d Law
