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ehidna [41]
3 years ago
11

What energy transformations take place when you eat a taco and then go for a jog

Physics
1 answer:
sesenic [268]3 years ago
6 0

Answer:

Chemical to kinetic and thermal.

Explanation:

You would eat the food (chemical) than you would jog and move around (kinetic). While running your body would also give off heat (thermal).Than your body would sweat to cool itself down.

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A 6 kilogram block in outer space is moving at -100 m/s (to the left). It suddenly experiences three forces as shown below (in t
Blizzard [7]

Answer:

x = 1474.9 [m]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

We must understand that when forces are applied on the body, they tend to slow the body down to stop it.

So as the body continues to move to the left, it is slowing down. Therefore we must calculate this deceleration value using Newton's second law. We must perform a sum of forces on the x-axis equal to the product of mass by acceleration. With leftward movement as negative and rightward forces as positive.

ΣF = m*a

10 +12*sin(60)= - 6*a\\a = - 3.39[m/s^{2}]

Now using the following equation of kinematics, we can calculate the distance of the block, before stopping completely. The initial speed must be 100 [m/s].

v_{f}^{2} =v_{o}^{2}-2*a*x

where:

Vf = final velocity = 0 (the block stops)

Vo = initial velocity = 100 [m/s]

a = - 3.39 [m/s²]

x = displacement [m]

0 = 100^{2}-2*3.39*x\\x=\frac{10000}{2*3.39}\\x=1474.9[m]

4 0
3 years ago
A pendulum has a period of 1.69 s on earth. what is its period on mars, where the acceleration of gravity is about 0.37 that on
love history [14]
The formula for the period of the pendulum is
T=2 \pi  \sqrt{ \frac{L}{g} }=
where L is the pendulum's length and g the gravitational acceleration.

Labeling with E the Earth and with M Mars, we can write the period of the pendulum on Earth as
T_E = 2 \pi  \sqrt{ \frac{L}{g_E} }
and the period of the pendulum on Mars as
T_M = 2 \pi  \sqrt{ \frac{L}{g_M} }

if we calculate the ratio, we get
\frac{T_M}{T_E}=  \sqrt{ \frac{g_E}{g_M} }
but we know that the gravitational acceleration on Mars is 0.37 times the gravitational acceleration on Earth:
g_M = 0.37 g_E
Substituting into the formula, we find
\frac{T_M}{T_E}= \sqrt{ \frac{1}{0.37} }=1.64
And so, the period of the pendulum on Mars is
T_M = 1.64 T_E = 1.64 (1.67 s)=2.78 s
8 0
3 years ago
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What force pulls all objects with mass toward<br> one another?
Vilka [71]
Gravity

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5 0
3 years ago
When a cold can of soda is insulated, the heat flow into the can on a hot day ____. a. increases c. stays the same b. decreases
telo118 [61]
The answer is decrease
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The implication is that tilted sedimentary layers observed to day mist have been subjected to tectonic forces

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