Hi
I belive you add the top side (4) plus the bottom side (9.5) witch would equal 13.5 times the hieght (3) equals 40.5 divided by 2 equals 20.25. the area is 20.25ft squared
another way to do it
4+9.5= 13.5
13.5×3= 40.5
40.5÷2= 20.25ft
2x + 5y = 34
x+2y = 14
Multiply the second equation by two to create like terms for one variable.
2(x+2y = 14)
2x + 4y = 28
2x + 5y = 34
2x + 4y = 28 -- Subtract.
y = 34.28 = 6
Solve for x
x + 2(6) = 14
x + 12 = 14
x = 2
Check:
2 + 2(6) = 14
2 + 12 = 14
14 = 14
Answer:
X = 2
Y = 6
The average rate of change over some interval [a, b] is equal to the slope of the secant line from (a, h(a)) to (b, h(b)).
h(t) is a quadratic function, so its graph is a parabola, and in particular it's one that has a minimum of -4 when t = 2.
The secant line over an interval [a, b] will have a negative slope if the distance from a to 2 is larger than the distance from b to 2.
(A) If a = 4 and b = 5, then |a - 2| = 2 and |b - 2| = 3, so the slope and hence average rate of change is positive.
(B) If a = -1 and b = 5, then |a - 2| = 3 and |b - 2| = 3, so this ARoC is zero.
(C) If a = 0 and b = 4, then |a - 2| = 2 and |b - 2| = 2, so this ARoC is also zero.
(D) If a = -1 and b = 4, then |a - 2| = 3 and |b - 2| = 2, so this ARoC is negative.
