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juin [17]
3 years ago
10

In the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O, an equivalence point occurs when 23.1 mL of 0.2055 M NaOH is added to a 25.0

mL portion of H2SO4. What is the [H2SO4]?
Chemistry
1 answer:
nekit [7.7K]3 years ago
8 0
            moles NaOH = c · V = 0.2055 mmol/mL · 23.1 mL = 4.74705 mmol
            moles H2SO4 = 4.74705 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.373525 mmol
Hence
            [H2SO4]= n/V = 2.373525 mmol / 25.0 mL = 0.09494 M
The answer to this question is  [H2SO4] = 0.09494 M

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Answer:

See explanation below (Brainlist please)

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An acidic hydrogen, is the atom of hydrogen which is more propense to undergo an acid base reaction, and form a stable ion or molecule in the process.

In other words, is the hydrogen that is more vulnerable to get substracted in an acid base reaction to form another compound.

Knowing this information, gives us an idea of how a molecule can be formed and which kind of compound is formed.

Now, in this question, we have 5 molecules. Each of them is either a ketone or aldehyde, so this mean that we have the carbonile group (C = O), which means that is easier to identify the acidic hydrogen. This is because the Carbonile group is an attractor group, so, it will attract the charges by inductive effect (in some cases by resonance), and the molecule is more stable.

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b) Propanal happens something similar to acetaldehyde, the terminal hydrogen cannot be substracted, and carbon 3, once the hydrogen is gone, the negative charge cannot be stabilized by resonance, so hydrogens of carbon 2 can do this.

c) in the case of acetone, is easier to look because we only have the C = O between two methyl group, so you can use either carbon 1 or 3 to do the job.

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e) Finally in ciclopentanone, the most acidic hydrogen would be carbon 2 or 5.

See picture for a better understanding.

Hope it helps.

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