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3 years ago

When blood moves from an atrium to a ventricle, it must pass through a __________

Chemistry

2 answers:

tangare [24]3 years ago

4 0

When blood moves from an atrium to a ventricle, it must pass through a one-way valve.

coldgirl [10]3 years ago

3 0

Answer:

Right side of the heart

Explanation:

Blood enters the heart through two large veins, the inferior and superior vena cava, emptying oxygen-poor blood from the body into the right atrium of the heart. As the atrium contracts, blood flows from your right atrium into your right ventricle through the open tricuspid valve.

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Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 1.731.

Amanda [17]

Answer:

The answer to your question is letter c) 6.09 g of sodium and 9.38 g of chlorine.

Explanation:

This problem is solve using rule of three

We know that the proportion Sodium to Chloride is 1 to 1 in sodium chloride, so we have to look for this proportion in the options

AM Sodium = 23 g

AM Chlorine = 35.5 g

Sodium Chlorine

23 g ---------------- 1 mol 35.5 g -------------- 1 mol

1713.73g ------------- x 2666.6 g ------------- x

x = 1713.73/23 = 74.51 x = 2666.6/35.5 = 75.12

These values are very similar, we have to look for the proportion in the options

a) 6.09g of sodium = 0.26 mol

4,87 g of chlorine = 0.14 mol These numbers are not very similar

b) We have 0.26 mol of Na

0.037 mol of Cl This is not the answer

c) We have 0.26 mol of Na

0.26 mol of Cl These numbers are the same, the proportion is 1:1, this is the answer

d) We have 0.26 mol of Na

0.36 mol of Cl This is not the answer

8 0

3 years ago

Create an element card that has the following information:

Shtirlitz [24]

Answer:

Atomic number:6

Atomic mass:12.011

Chemical symbol:C

Name of element: Carbon, Carbone (french)

Image is in my explanation

Explanation:

6 0

3 years ago

The sample of 15.0 g of KCl is dissolved into a solution with a total volume of 250.0 mL. What is the molarity of KCl in the sol

lina2011 [118]

Answer:

0.805 M.

Explanation:

Hello!

In this case, since the molarity of a solution is computing by dividing the moles of solute over the volume of solution in liters (M=n/V), for 15.0 g of potassium chloride (74.55 g/mol) we compute the corresponding moles:

$n=15.0gKCl*\frac{1molKCl}{74.55gKCl}=0.201molKCl$

Next, since the volume is 0.2500 in liters, the molarity turns out:

$M=\frac{0.201mol}{0.2500L} \\\\M=0.805M$

Best regards!

3 0

3 years ago

Nuclear reactions involves

Finger [1]

Nuclear reaction involves two reacting particles a heavy target nucleus and a light bombarding particle and produces two new particles a heavier product nucleus and a lighter ejected particle.

6 0

3 years ago

You need to make 10.0 L of 1.2 M KNO3. What molar ( concentration) would the potassium nitrate solution need to be if you were t

solniwko [45]

Answer:

2.5L [NaCl] concentrate needs to be 4.8 Molar solution before dilution to prep 10L of 1.2M KNO₃ solution.

Explanation:

Generally, moles of solute in solution before dilution must equal moles of solute after dilution.

By definition Molarity = moles solute/volume of solution in Liters

=> moles solute = Molarity x Volume (L)

Apply moles before dilution = moles after dilution ...

=> (Molarity X Volume)before dilution = (Molarity X Volume)after dilution

=> (M)(2.5L)before = (1.2M)(10.0L)after

=> Molarity of 2.5L concentrate = (1.2M)(10.0L)/(2.5L) = 4.8 Molar concentrate

6 0

3 years ago