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Brums [2.3K]
3 years ago
13

How many grams are in 6.50 moles of h2so4?

Chemistry
2 answers:
Reika [66]3 years ago
8 0

Answer is: 638g

Hope this helps!

GREYUIT [131]3 years ago
7 0
You multiply 6.50 by the molar mass of H2SO4. 
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A cleaning bottle contains 83.1 g of ammonia. How many molecules of ammonia are in the bottle?
Tasya [4]

Answer:

2.94 x 10^2^4

Explanation:

First we need to find out how many moles of ammonia there are, using the formula: Mass = mr x moles.

We know the mass is 83.1g, now we need to find the mR of ammonia - NH3.

N = 14, H = 1, so 14 + (3x1) = an mr of 17.

Moles = mass/ mr = 83.1/17 = 4.8882

Now we can multiply the moles by avogadro's constant to find the number of molecules:

4.8882 x (6.02 x 10^2^3 ) = 2.94 x 10^2^4 molecules of ammonia

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3 years ago
If a molecule can hydrogen bond, does it guarantee that it will have a higher boiling point than a molecule that cannot? Explain
saul85 [17]

Answer:

a): not necessarily due to London Dispersion Forces and dipole-dipole interactions.  

b): not necessarily due to London Dispersion Forces.

Explanation:

There are three major types of intermolecular interaction:

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The melting point of a substance is a result of all three forces, combined.

Note that the more electrons in each molecule, the stronger the London Dispersion Force. Generally, that means the more atoms in each molecule, the stronger the London dispersion force. The strength of London dispersion force between large molecules can be surprisingly strong.

For example, \rm H_2O (water) molecules are capable of hydrogen bonding. The melting point of \rm H_2O at \rm 1\; atm is around 0 \; ^{\circ}\rm C. That's considerably high when compared to other three-atom molecules.

In comparison, the higher alkane hexadecane (\rm C_{16}H_{34}, straight-chain) isn't capable of hydrogen bonding. However, under a similar pressure, hexadecane melts at around 18\; ^{\circ}\rm C above the melting point of water. The reason is that with such a large number of atoms (and hence electrons) per molecule, the London dispersion force between hexadecane molecules could well be stronger than that the hydrogen bonding between water molecules.

Similarly, the dipole moments in HCl (due to the highly-polar H-Cl bonds) are much stronger than those in hexadecane (due to the C-H bonds.) However, the boiling point of hexadecane under standard conditions is much higher (at around 287\; \rm ^\circ C than that of HCl.

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3 years ago
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Answer:

B and C is corrent i got it right on edge

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