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Brums [2.3K]
3 years ago
13

How many grams are in 6.50 moles of h2so4?

Chemistry
2 answers:
Reika [66]3 years ago
8 0

Answer is: 638g

Hope this helps!

GREYUIT [131]3 years ago
7 0
You multiply 6.50 by the molar mass of H2SO4. 
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Mg is the symbol of Magnesium and Cl is the symbol of chlorine ( but when Cl is a compound it will be Choride)
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3 years ago
What do chemists use percent yield calculations for in the real world?
STALIN [3.7K]

Answer:

C. To determine how efficient reactions are.

D. To determine how much reactant they need.

Explanation:

When you are doing a reaction, you are hoping for a percent yield to close of 100%. You make the reaction and determine how many product you obtain. If you know the percent yield of a reaction you can calculate the amount of reactant you need to obtain a determined amount of product.

Having this in mind:

A. To balance the reaction equation.  false. To calculate percent yield you need to balance the reaction before. You don't use percent yield to balance the reaction

B. To determine how much product they will need.  false. You determine how much product you obtain after the reaction. How much product you need is independent of percent yield

C. To determine how efficient reactions are.  true. A way to determine efficience of a reaction is with percent yield. An efficient reaction has a high percent yield.

D. To determine how much reactant they need. true. If you know percent yield of a reaction you can know how many reactant you must add to obtain  the amount of product you want.

8 0
3 years ago
List 4 indicators that a chemical change has probably occurred
aivan3 [116]
1. Change in color
2. Formation of bubbles
3. Formation of a precipitate
4. Begins to make an odor
6 0
3 years ago
A student dissolves 6.2g of aniline c6h5nh2 in 350.ml of a solvent with a density of 1.04/gml . the student notices that the vol
Troyanec [42]

Answer : The correct answer for molarity = 0.19 \frac{mol}{L} and Molality = 0.18 \frac{mol}{Kg}.

Given : Mass of aniline = 6.2 g

Volume of solvent = 350 mL Density of solvent = 1.04 g/mL

1) Molarity : It is defined as number of moles of solute present in Litre of solution . It is expressed as :

Molarity(M) = \frac{moles of solute(mole)}{volume of solution (L)}\

Molairty can be found in following steps :

Step 1 : To calculate mole :

Mole of solute can be calculate using mole formula :

Mole of solute = \frac{given mass of solute (g)}{molar mass of solute\frac{g}{1 mol}}

Molar mass of aniline (C₆H₅NH₂) = 93.13 \frac{g}{1 mol}

Mass of aniline = 6.2 g

Plugging values in mole formula :

Mole  =  \frac{6.2 g}{93.13 \frac{g}{1 mol}}

Mole = 0.0665 mol

Step 2 : To find volume of solution

Volume of solution = volume of solute + volume of solution

Since addition of aniline does not change final volume , so volume of solvent = volume of solution. Since volume is given in mL , so it need to be converted to L .

1 L = 1000mL

Volume of solution = \frac{350 mL}{1000mL}  * 1 L

Volume of solution = 0.350 L

Step 3: Plug value of mole and volume in molarity formula :

Molarity = \frac{0.0665 mol}{0.350 L }

Molarity = 0.19 M or 0.19 \frac{mol}{L}

------------------------------------------------------------------------------------------

2) Molality : It is defined as mole of solute present in Kilogram of solvent . It can be expressed as :

Molality (m) = \frac{mole of solute (mol)}{Kilogram of solvent (Kg)}

Following are the steps to calculate molality :

Step 1: To find mole of Solute :

Mole of solute can be found out using mole formula . It is same as done for molarity .

Mole = 0.0665 mol

Step 2 : To find kilogram of solvent :

Mass of solvent can be calculated using density formula as :

Density \frac{g}{mL} = \frac{mass (g) }{volume (mL)}

Plugging value in density formula :

1.04 \frac{g}{mL}  =  \frac{ mass }{350 mL}

Multiplying both side by 350 mL

1.04 \frac{g}{mL} * 350 mL = \frac{x}{350 mL } * 350 mL

Mass of solvent = 364 g

Since mass is in g, it need to be converted to Kg . ( 1 Kg = 1000 g )

Mass of solvent = \frac{364 g}{1000g} * 1 Kg

Mass of solvent = 0.364 Kg

Step 3: Plug values of mole and Kg in molality formula :

Molality = \frac{0.0665 mol}{0.364 Kg}

Molality = 0.18 m or 0.18 \frac{mol}{Kg}

3 0
3 years ago
In science, a summary of observed behavior is referred to as a(n)
umka2103 [35]

Answer:

Law

Explanation:

A law is a summary of observed (measurable) behavior, whereas a theory is an explanation of behavior. A law tells what happens; a theory (model) is our attempt to explain why it happens.

5 0
3 years ago
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