We will calculate the synodic period, as it is the time it takes for the object to reappear at the same point in the sky with respect to the sun, when viewed from Earth. For this problem we will apply the concepts related to the orbital period ( Kepler's Third Law ) which is determined as
Where,
r = Radius/Distance
G = Gravitational Universal Constant
m = Mass of the object
Replacing,
Answer:
1×10^2
Explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
1. 0°C
2. Motion
3. Joules
4. Thermometer
5. Gas
6. Less
7. Temperature
Answer:
x = 0.0537 m or 5.37 cm
Explanation:
Given:
spring constant'k'= 4900 N/m
radius 'r' =0.029 m
Area 'A' =r²π = 0.029²π => 2.6 x m²
Here, Pressure 'P' is given by,
Pressure = Force / Area
And we know that, for a spring :
F = kx, where k is the spring constant and x is the change in length.
P = kx/A
As P = 101325 Pa
101325 = 4900x / ( 2.6 x )
x = 0.0537 m or 5.37 cm
Answer:
P = 9800 [Pa]
Explanation:
In order to calculate the pressure at the bottom, we must use the following formula.
P = Ro*g*h
where:
P = pressure [Pa] (units of pascals)
Ro = density of the water = 1000 [kg/m³]
g = gravity acceleration = 9.8 [m/s²]
h = height = 1 [m] (because its half of the portion, the full height is 2 m)
P = 1000*9.8*1
P = 9800 [Pa]