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saul85 [17]
3 years ago
15

What event was seen as a symbol of the gradual relationship improvements between the United States and the Soviet Union as the C

old War was coming to an end?
A. The Soviet space center and the US space center signed a treaty agreeing to put the past behind them and work together for future space endeavors.
B. A handshake that occurred between the commanders of a US and Soviet space craft that were involved in a joint moon mission.
C. Astronauts from both countries taking a trip to the moon together aboard one space craft.
D. A male astronaut from the Soviet Union and a female astronaut from the US walked on the moon together.
Physics
1 answer:
Olegator [25]3 years ago
4 0

Answer:

I think the answer is b but i cannot confirm cuz this is a challenging question

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A branch falls from a tree How fast is the branch moving after 0 28 seconds
egoroff_w [7]

Answer:

c. 2.7 m/s

Explanation:

v = a.t + v_{0}\\a = g = 9.81 m/s^{2}} \\t=0.28 s \\v_{0} = 0\\=> v = 9.81 * 0.28 = 2.74 m/s

3 0
3 years ago
What does digital media allow you to do?
kifflom [539]
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A cube of plastic 1.2x10^-5 km on a side has a mas of 1.1 g. what is its density in g/cm^3?
Mamont248 [21]
Density = mass / volume

mass = 1.1 g

volume = length of side ^ 3 = [1.2 * 10^-5 km * 100000 cm/km]^3 = [1.2 cm]^3 = 1.728 cm^3

density = 1.1 g / 1.728 cm^3 = 0.64 g / cm^3

 
5 0
4 years ago
A school bus moves at speed of 35 mi/hr for 20 miles. How long will it take the bus to get to school
ludmilkaskok [199]

Answer:

Explanation:

Assuming school is at the end of the 20 mile route, then

20 mi / 35 mi/hr = 0.57142...hr

which is about 34 minutes 17 seconds

6 0
3 years ago
Holding onto a tow rope moving parallel to a frictionless ski slope, a 68.7 kg skier is pulled up the slope, which is at an angl
Furkat [3]

Answer:

a) F = 78.606\,N, b) F = 88.911\,N

Explanation:

a) Let consider two equations of equilibrium, the first parallel to ski slope and the second perpendicular to that. The equations are, respectively:

\Sigma F_{x'} = F - m\cdot g \cdot \sin \theta = 0\\\Sigma F_{y'} = N - m\cdot g \cdot \cos \theta = 0

The force on the skier is:

F = m \cdot g \cdot \sin \theta

F = (68.7\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot \sin 6.7^{\textdegree}

F = 78.606\,N

b) The equations of equilibrium are the following:

\Sigma F_{x'} = F - m\cdot g \cdot \sin \theta = m\cdot a\\\Sigma F_{y'} = N - m\cdot g \cdot \cos \theta = 0

The force on the skier is:

F = m\cdot (a + g \cdot \sin \theta)

F = (68.7\,kg)\cdot (0.150\,\frac{m}{s^{2}}+9.807\,\frac{m}{s^{2}}\cdot \sin 6.7^{\textdegree})

F = 88.911\,N

3 0
3 years ago
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