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2 years ago

2 Jupiter orbits the sun in a nearly circular path with radius 7.8x10^11m. The orbital period of Jupiter is 12 years.

Physics

1 answer:

bazaltina [42]2 years ago

4 0

Mass of Jupiter=1.9×10

㎏=M

Mass of Sun=1.99×10

㎏=M

Mean distance of Jupiter from Sun=7.8×10

m=r

G=6.67×10

−11

N㎡㎏

−2

Gravitational Force, F=

(7.8×10

)

6.67×10

−11

×1.9×10

×1.99×10

F=4.16×10

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Now Total volume of bobble is

$\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\$

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