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2 years ago

2 Jupiter orbits the sun in a nearly circular path with radius 7.8x10^11m. The orbital period of Jupiter is 12 years.

Physics

1 answer:

bazaltina [42]2 years ago

4 0

Mass of Jupiter=1.9×10

㎏=M

Mass of Sun=1.99×10

㎏=M

Mean distance of Jupiter from Sun=7.8×10

m=r

G=6.67×10

−11

N㎡㎏

−2

Gravitational Force, F=

(7.8×10

)

6.67×10

−11

×1.9×10

×1.99×10

F=4.16×10

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Marrrta [24]

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3 years ago

A(n) 93 kg clock initially at rest on a horizontal floor requires a(n) 610 N horizontal force to set it in motion. After the clo

denpristay [2]

Answer:0.669

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Given

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Initial force required to move it 610 N

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thus 613 force is required to overcome static friction

$\mu _smg=610$

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