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yawa3891 [41]
3 years ago
13

Simplify the expression 19-(-8)-(14)=

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0
Use pemdas
19--8=27-14=13
Therefore 13 is your answer. <span />
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Dusty is dividing 700 pencils into groups of 25 for each classroom. How many classrooms are there?
natka813 [3]

Answer:

28

Step-by-step explanation

28 times 25 is 700

5 0
3 years ago
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Which property of addiction does 8+0=8 illustrate
Rus_ich [418]

Answer:

The statement represents the IDENTITY PROPERTY OF ADDITION.

Step-by-step explanation:

Here, the given expression is  8 + 0 = 8

IDENTITY ELEMENT :  Identity element is a special type of element in a given  set of system, such that any number remains UNALTERED if operated with the identity element.

⇒  a + X  = X  for, a   ≡  IDENTITY ELEMENT

Now,  8  +   0  =   8

Comparing it with the above equation , we get

0 ≡ IDENTITY ELEMENT in the given Binary operation of Addition.

Hence,  the statement represent the IDENTITY PROPERTY OF ADDITION.

4 0
3 years ago
Which statement is true? HELP!
Vitek1552 [10]

Answer: C

Step-by-step explanation:

I remember this test

6 0
3 years ago
In a right triangle, CosA=0.352 and SinA=0.936 What is the approximate value of tanA?
mr_godi [17]
\tan A=\frac{\sin A}{\cos A}

Proof: \sin\div\cos=\frac{o}h\div\frac{a}h=\frac{o}h\times\frac{h}a=\frac{oh}{ha}=\frac{o}a=\tan

\cos A=0.352,\ \sin A=0.936

\tan A=\frac{0.936}{0.352}

\boxed{\tan A=2.65\overline{90}} <em>(round as needed)</em>
6 0
3 years ago
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[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
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