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yawa3891 [41]
4 years ago
13

Simplify the expression 19-(-8)-(14)=

Mathematics
1 answer:
nikdorinn [45]4 years ago
3 0
Use pemdas
19--8=27-14=13
Therefore 13 is your answer. <span />
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Simplify this equation 3x^2×4x^5y^4
Natalija [7]

Answer:

(3•2^2x^7y^4)

Step-by-step explanation:

((3x2 • 4) • x5) • y4

8 0
4 years ago
USE Six digits are given. 7 2 0 6 8 4 Answer the questions about these digits. Be sure to use commas when writing your numbers.
luda_lava [24]

Answer:

a) 888,888

b) 200,00

c) 888,888-200,000=688,888

step-by-step explanation:

the biggest number possible is 888,888 because 8 is the largest number and the question doesn't say that you have to use each number

200,000 is the smallest number because outside 0, 2 is the second-smallest number, and since 000,000 isn't a number 200,000 is the next best thing

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3 years ago
FACTOR<br>h² + 9hj + 14j²​
Kryger [21]

Answer:

(h+7j)*(h+2j)

Step-by-step explanation:

h^2+7hj+2hj+14j^2

h*(h+7j)+2j*(h+7j)=(h+7j)*(h+2j)

4 0
3 years ago
Read 2 more answers
The population of a certain city is decreased by 5332 in 20 years express the change in population per year as a unit rate
3241004551 [841]

Answer:

266.6 per year

Step-by-step explanation:

53392 / 20 = 266.6

= 266.6 per year

5 0
3 years ago
The swimming pool at Spring Valley High School is a rectangle with a width of 70 meters and a length of 30 meters. Around the pe
kotykmax [81]

The expression that can be used to find the area of the tiled floor is 4w² + 200w

<h3>Area of rectangle</h3>

  • Original rectangle:

Length = 70 Meters

Width = 30 meters

Area = length × width

= 70 × 30

= 2100

  • New rectangle(including tiled floor):

Length = 70 + 2w meters

Width = 30 + 2w meters

Area = length × width

= (70+2w) (30+2w)

= 2100 + 140w + 60w + 4w²

= 4w² + 200w + 2100

Area of the tiled floor = Area of new rectangle - area of old rectangle

= (4w² + 200w + 2100) - 2100

= 4w² + 200w + 2100 - 2100

= 4w² + 200w

Learn more about area of rectangle:

brainly.com/question/13048427

#SPJ1

6 0
2 years ago
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