So what we know:
-Atomic Mass = Protons + Neutrons
-Atomic Number is the number of protons
Magnesium's atomic number is 12, so the natural occurring isotope for magnesium is Mg-12 (12 protons and 12 neutrons). Added up we have an atomic mass of 24 amu. Which means if we added one neutron in Mg-13, our atomic mass would be 25 amu.
We can use the equation:
(amu of isotope 1)x + (amu of isotop 2)(x-1) = Average atomic mass
where isotope 1 is the fractional abundance we're solving for.
Plugged in it looks like this:
24x + 25(1-x) = 24.3
Now to solve for x:
24x + 25 - 25x = 24.3
-x + 25 = 24.3
-x = -.7
x = .7
So in this case, the fractional abundance of Mg-12 would be .7, or 70%.<span />
Answer:
The three statements are true
Explanation:
For the reaction:
I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)
State oxidation of iodine in I₂O₅ is:
5 O²⁻ = 10⁻
As you have 2 I and the molecule has no charge, <em>oxidation state of I is +5</em>.
The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means <em>the carbon is oxidized</em>
<em />
An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being <em>the oxidizing agent</em>
<em></em>
Thus,<em> the three statements are true</em>.
<span>
<span> 250g H2SO4 x 1moleH2SO4/ 98g mole H2SO4 x 4moles Oxygen/1moleH2SO4 x 1moleOxgen/16g Oxygen
= 163.27g Oxygen
my figures aren't exact....so it's 160g </span>
</span>
Its going to be 2.81 x 1023 atoms
