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2 years ago

How many elements are in the following equation? salt pure water(NaC/ + H2O)

Chemistry

2 answers:

vesna_86 [32]2 years ago

8 0

Hey! I believe that there are 4 elements in the equation.

AlexFokin [52]2 years ago

6 0

Answer:

Explanation:

Sodium Na, Carbon C, hydrogen H2, Oxygen O

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How many mole of H2 will be produced if 0.500 grams of magnesium is reacted with 10.00mL of 2.0 M HCl?

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Yes, you're right the answer is 0,02 moles.

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3 years ago

What characteristic of gases makes them different from liquids or solids?

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<span>The particles are far apart from each other.</span>

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2 years ago

A chemist has 2. 0 mol of methanol (CH3OH). The molar mass of methanol is 32. 0 g/mol. What is the mass, in grams, of the sample

natima [27]

The mass, in grams, of the sample of methanol (CH₃OH) is 64 grams.

<h3>How we calculate mass from moles?</h3>

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M = molar mass

In the question that:

Moles of methanol = 2mole

Molar mass of methanol = 32g/mole

On putting these values in the above equation, we get

W = n × M

W = 2mole × 32g/mole = 64g

Hence, 64 grams is the mass of the sample.

To know more about moles, visit the below link:

brainly.com/question/15374113

6 0

2 years ago

An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit

Anon25 [30]

<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol

<u>Explanation:</u>

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of triprotic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL$

Putting values in above equation, we get:

$3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

$0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol$

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

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2 years ago

Which type of drug commonly marketed to consumers does not require a prescription?

Nimfa-mama [501]

C. pain reliever
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2 years ago