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vazorg [7]
3 years ago
15

Sodium is a soft, white metal that reacts violently with water. Chlorine is a poisonous yellow-green gas. During the chemical re

action between sodium and chlorine, table salt is produced. Which of the following statements correctly compares and contrasts the reactants with the resulting products used in a chemical equation?
A. The reactants are dangerous and the product can be eaten
B. The reactants and the products observe the law of conservation of mass
C. The reactants are a solid and a gas and the product is a gas
D. The reactants and the products are the same color
Chemistry
1 answer:
kompoz [17]3 years ago
6 0

Answer:

B. The reactants and the products observe the law of conservation of mass

Explanation:

The reaction equation is given as:

            2Na  +  Cl₂  →   2NaCl

Such a chemical reactions usually obeys the law of conservation of mass. The law states that "in a chemical reaction, matter is neither created nor destroyed but bonds are rearranged".

  • So, the most correct thing is that reactants and products observe the law of conservation of mass.
  • The number of atoms on both sides of the expression will be the same.
  • Therefore, option B is correct.  
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The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichl
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Complete Question

A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane

The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?

Answer:

The mass of  caffeine extracted is  P =  39.8 \ mg

Explanation:

From the question above  we are told that

    The  K value is  K =  4.6

     The  mass of the caffeine is  m  = 40 mg

      The  volume of water is  V  = 2 mL

      The volume  of caffeine is  v_c =  2 mL

     The number of times the extraction was done is  n =  3

Generally the mass of  caffeine that will be  extracted is  

           P =  m  *  [\frac{V}{K *  v_c + V} ]^3

substituting values  

           P =  40   *  [\frac{2}{4.6 *  2 + 2} ]^3

           P =  39.8 \ mg

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