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igomit [66]
3 years ago
9

In a recrystallization (a technique that you will encounter later in the semester), a solid is dissolved in a solvent and later

the solvent is removed. if a mp of the sample is taken while the sample is still moist with solvent, what effect would that have on the mp of the sample?
Chemistry
1 answer:
grandymaker [24]3 years ago
7 0

In a recrystallization (a technique that you will encounter later in the semester), a solid is dissolved in a solvent and later the solvent is removed. if a mp of the sample is taken while the sample is still moist with solvent then melting point will not come out to be accurate, as solvent is still present in the compound and that results in the variation of the melting point as the residual solvent will serves as impurities , and due to the presence of these impurities, melting point vary and does not come to be accurate .

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At what temp will a gas be at if you allow it to expand from an original 456 mL to 65°C to 3.4 L
alexira [117]
We use the gas law named Charle's law for the calculation of the second temperature. The law states that,
                                          V₁T₂ = V₂T₁
Substituting the known values,
                                (0.456 L)(65 + 273.15) = (3.4 L)(T₁)
                                             T₁ = 45.33 K
5 0
3 years ago
Read 2 more answers
A solution is prepared at that is initially in benzoic acid , a weak acid with , and in sodium benzoate . Calculate the pH of th
Kisachek [45]

Answer:

pH=4.1

Explanation:

Hello,

In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:

pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1

Regards.

3 0
3 years ago
Select multiple choices.<br><br> Thank you
AnnZ [28]
D, systems of writing
4 0
3 years ago
To interconvert the concentration units molality (m) and mass percent, you must also know the density of the solution. A) True B
uranmaximum [27]

Answer:

The correct answer is option false.

Explanation:

Molality of the solution defined as moles of substance present in 1 kilogram of   solvent.

Moles = \frac{Mass of solute}}{\text{molar mass of solute}}

Molality=\frac{Moles}{\text{Mass of solvent(kg)}}

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

(w/w\%)_=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.

Mass of solution = Mass of solute + Mass of solvent

7 0
3 years ago
3.-4.
creativ13 [48]

The power for the first tank is 2kW  and the second tank is 150 kw for the theoretical pumping power lifts a solution with a density of 1200 kg/m³ from a tank to a reservoir.

<h3>What is power?</h3>

Power is the amount of energy in kilowatt which is required to do some work that needs energy known as power it is the multiplication of pressure and the flow of liquid.

Power for the tank = pressure of water × flow of water

Substituting the value,

power = 1 × 2 = 2 kW = P1

power = 10 × 15 = 150 kW = P2

Therefore,  a solution with a density of 1200 kg/m³ from a tank to a reservoir power for the first tank is 2kW  and for the second tank is 150 kW for the theoretical pumping power lifts.

Learn more about power, here:

brainly.com/question/24091709

#SPJ1

3 0
1 year ago
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