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Free_Kalibri [48]
3 years ago
6

What can be said about a reaction with H = 62.4 kJ/mol and S = 0.145 kJ/(mol·K)?

Chemistry
2 answers:
Rainbow [258]3 years ago
7 0

The answer is "It is spontaneous at 500 k"

Zigmanuir [339]3 years ago
3 0
Answer:

At 430.34 K the reaction will be at equilibrium, at  T > 430.34 the reaction will be spontaneous, and at T < 430.4K the reaction will not occur spontaneously.

Explanation:

1) Variables:

G = Gibbs energy
H = enthalpy
S = entropy

2) Formula (definition)

G = H + TS

=> ΔG = ΔH - TΔS

3) conditions

ΔG < 0 => spontaneous reaction
ΔG = 0 => equilibrium
ΔG > 0 non espontaneous reaction

4) Assuming the data given correspond to ΔH and ΔS

ΔG = ΔH - T ΔS = 62.4 kJ/mol + T 0.145 kJ / mol * K

=>  T = [ΔH - ΔG] / ΔS

ΔG = 0 =>  T = [ 62.4 kJ/mol - 0 ] / 0.145 kJ/mol*K = 430.34K

This is, at 430.34 K the reaction will be at equilibrium, at  T > 430.34 the reaction will be spontaneous, and at T < 430.4K the reaction will not occur spontaneously.

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Explanation:

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Which statement is true about a polyatomic ion?
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Explanation:

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2 years ago
The equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfe
Novay_Z [31]

Answer:

0.23 V.

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<em>∵ ΔG° = -RT lnK.</em>

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5 0
3 years ago
What volume in milliters would give 12.0 grams of NaOH from a 2.0 M NaOH solution?
zavuch27 [327]

Answer:

V = 150 mL

Explanation:

Hello!

In this case, since the molarity of a solution is computed via:

M=\frac{n}{V}

Whereas we are asked to compute the volume:

V=\frac{n}{M}

Thus, we first compute the moles in 12.0 g of NaOH as its molar mass is about 40.0 g/mol:

n=\frac{12.0g}{40.0g/mol}=0.3mol

Thus, at first instance, the volume liters is:

V=\frac{0.3mol}{2.0mol/L} \\\\V=0.15L

Which in milliliters is:

V=0.15L*\frac{1000mL}{1L}\\\\V=150mL

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3 years ago
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