What is the net ionic equation for the reaction of solid iron with aqueous copper sulfate? (Hint: First use the activity series
to write the formula unit equation!) 1. 2 Fe(s) + 3 CuSO4(aq) → Fe2(SO4)3(s) + 3 Cu(s) 2. 2 Fe(s) + 3 Cu2+(aq) + 3 SO2− 4 (aq) → Fe2(SO4)3(s) + 3 Cu(s) 3. No reaction occurs. 4. 2 Fe(s) + 3 CuSO4(aq) → Fe2(SO4)3(aq) + 3 Cu(s) 5. 2 Fe(s) + 3 Cu2+(aq) + 3 SO2− 4 (aq) → 2 Fe3+(aq) + 3 SO2− 4 (aq) + 3 Cu(s) 6. 2 Fe(s) + 3 Cu2+(aq) → 2 Fe3+(aq) + 3 Cu(s)
1 answer:
Answer:
6. 2 Fe(s) + 3 Cu2+(aq) → 2 Fe3+(aq) + 3 Cu(s).
Explanation:
The reaction of solid iron with aqueous copper sulfate is an example of a single displacement type of reaction.
Half equations
2 Fe(s) → 2Fe2+(aq)
3CuSO4(aq) → 3Cu(s) + 3SO4^2-(aq)
Net ionic equation:
2Fe(s) + 3Cu2+(aq) → Fe2+(s) + 3Cu(aq)
2Fe(s) + 3CuSO4(aq) → Fe2(SO4)3(s) + 3Cu2+(aq)
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