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Natali5045456 [20]
3 years ago
9

A student needs to conduct a reaction that combines chemicals A and B to synthesize product AB. If we write this as a chemical e

quation it looks like:
Chemistry
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:A+B - AB

Element a reaction with element b to create the newest element ab

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HBrO (aq) + H2O (l) ⇋ H3O+ (aq) + BrO- (aq)
joja [24]

Answer:

6.24 x 10-3 M

Explanation:

Hello,

In this case, for the given dissociation, we have the following equilibrium expression in terms of the law of mass action:

Ka=\frac{[H_3O^+][BrO^-]}{[HBrO]}

Of course, water is excluded as it is liquid and the concentration of aqueous species should be considered only. In such a way, in terms of the change x, we rewrite the expression considering an ICE table and the initial concentration of HBrO that is 0.749 M:

5.2x10^{-5}=\frac{x*x}{0.749-x}

Thus, we obtain a quadratic equation whose solution is:

x_1=-0.00627M\\x_2=0.00624M

Clearly, the solution is 0.00624 M as no negative concentrations are allowed, so the concentration of BrO⁻ is 6.24 x 10-3 M.

Best regards.

4 0
3 years ago
Read 2 more answers
Which of the following has the most energy?
iren2701 [21]
Ultraviolet rays has the most energy
8 0
3 years ago
a 100.0 g sample of a metal m is burned in air to produce 103.7 g of its oxide with the formula m2o. what is the atomic mass of
Ahat [919]
The molar mass should be 14.898g/mol. I used the equation 100gx(1/xg/mol)x(1mol/2mol)x(16g/mol+x)/1)=103.7 and solve for x. I found that equation using stoichiometry and the equation 2m+1/2O2-->m2O The molar mass of the metal I set to x and the molar mass of the metal oxide is 16+x.
6 0
3 years ago
Complete combustion of 2.90g of a hydrocarbon produced 9.32g of CO2 and 3.18g of H2O. What is the empirical formula for the hydr
Olenka [21]

Answer;

= C3H5

Explanation and solution;

1 mole of CO2 contains 44 g, of which 12 g are carbon

Thus, mass of carbon in 9.32 g will be;

(12/44) × 9.32 g = 2.542 g

Mass of Hydrogen in 3.18 g of water;

= (2/18) × 3.18 g = 0.353 g

we then find the number of moles;

Moles of carbon ; 2.542 /12 = 0.2118 moles

Moles of Hydrogen = 0.353 moles

The ratios of C ; H ;

= 1 :  0.353 /0.2118

= 1 : 5/3

= 3: 5

Therefore; the empirical formula of the hydrogen carbon is; C3H5

5 0
3 years ago
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the covalent compound formaldehyde forms when one carbon atom, two hydrogen atoms, and one oxygen atom bond. write a chemical fo
tino4ka555 [31]
Formally CH2O OR HCHO
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