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tangare [24]
4 years ago
5

Which air mass provides the moisture that produces the clouds and precipitation?

Physics
1 answer:
Andreas93 [3]4 years ago
6 0
The MT is the air mass that provides the moisture that produces the clouds and precipitation. An air mass is a volume of air that is defined by its temperature and water vapor or moisture content .  MT is the abbreviation of marine time air mass. Air masses can control the weather for a relatively long time period from a period of days, to months, Most weather occurs along the periphery of these air masses at boundaries called fronts.
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Calcula la energía cinética der un vehículo de 1860kg 1ue se mueve a 50km/h​
PtichkaEL [24]

Answer:

Kinetic energy of the vehicle is

K = 1.79 \times 10^5 J

Explanation:

Kinetic Energy of the vehicle is given as

K = \frac{1}{2}mv^2

now we have

m = 1860 kg

v = 50 km/h

v = 50 \times \frac{5}{18}

v = 13.89 m/s

now we have

K = \frac{1}{2}(1860)(13.89)^2

K = 1.79 \times 10^5 J

4 0
3 years ago
How To achieve the largest resistance ?
nadya68 [22]

Answer:

material, eg copper, has lower resistance than steel.

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Explanation:

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3 years ago
Convert this number to standard notation: 1.4 x 10^-2*
Marysya12 [62]

Answer:

0.014

Explanation:

here

1.4 x 10^-2

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6 0
3 years ago
2) If the current in any circuit reach to infinity then its resistance becomes
In-s [12.5K]

Answer:

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4 0
3 years ago
Neutral hydrogen can be modeled as a positive point charge +1.6×10^−19C surrounded by a distribution of negative charge with vol
Archy [21]

Answer:

a) 1.082 × 10⁻¹⁹C  ( e = 1.6 × 10⁻¹⁹C)  

b) 3.466 × 10¹¹ N/C

Explanation:

a)

p(r) = -A exp ( - 2r/a₀)

Q = ₀∫^∞ ₀∫^π ₀∫^2xπ p(r)dV  =  -A  ₀∫^∞ ₀∫^π ₀∫^2π   exp ( - 2r/a₀)r² sinθdrdθd∅

Q = -4πA ₀∫^∞ exp ( - 2r/a₀)r²dr = -e

now using integration by parts;

A = e / πa₀³

p(r) =  - (e / πa₀³) exp (-2r/a₀)

Now Net charge inside a sphere of radius a₀ i.e Qnet is;

= e - (e / πa₀³)  ₀∫^a₀ ₀∫^π ₀∫^2π  r² exp (-2r/a₀)dr

= e - e + 5e exp (-2) = 1.082 × 10⁻¹⁹C  ( e = 1.6 × 10⁻¹⁹C)  

b)

Using Gauss's law,

E × 4πa₀ ² = Qnet / ∈₀

E = 4πa₀ ² × Qnet × 1/a₀²

E = 3.466 × 10¹¹ N/C

4 0
3 years ago
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