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VLD [36.1K]
3 years ago
8

Calculate the total displacement if a toy car starts at 0 moves 5cm to the left then 8cm to the right then 3 cm to the left

Physics
1 answer:
never [62]3 years ago
6 0
It’s a total of 16 cm because it starts at 0 moves then moves to left then the right then the left
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_ acceleration occurs when an object speeds up.<br> Answer<br> Positive
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_ acceleration occurs when an object speeds up.

Answer

Positive

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3 years ago
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Help. Please! I really need help. It’s timed, and I’m loosing points.
Archy [21]

Answer:

I think balanced

Explanation:

because there is a 2 on each arrow

5 0
3 years ago
A Ray of light falling on rough surface follows the laws of reflection but no image of the object placed before it is C explain
stepladder [879]

Answer:

The light rays falling on a rough surface does follow the laws of reflection. The light rays are incident parallel on the rough surface but due to uneven surface the light rays are not reflected parallel rather they are reflected in different direction. Hence, no image is formed.

4 0
3 years ago
4. X-ray radiation from diffraction and fluorescence instruments is a) Not very dangerous because the X-rays are absorbed in the
Dahasolnce [82]

Answer:

c) Very dangerous and users must not override devices designed to protect from exposures.

Explanation:

X-ray is a form of high energy electromagnetic radiation and are part of the electromagnetic spectrum.

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7 0
3 years ago
A boy is pulling a load of 150N with a string inclined at an angle 30 to the horizontal if the tension of string is 105N the for
Lorico [155]

The force tending to lift the load (vertical force) is equal to <u>22.5N.</u>

Why?

Since the boy is pulling a load (150N) with a string inclined at an angle of 30° to the horizontal, the total force will have two components (horizontal and vertical component), but we need to consider the given information about the tension of the string which is equal to 105N.

We can calculate the vertical force using the following formula:

VerticalForce=Force*Sin(30\° )=(BoysForce-StringForce)*\frac{1}{2}\\\\VerticalForce=(150N-105N)*\frac{1}{2}=VerticalForce=45N*\frac{1}{2}=22.5N

Hence, we can see that <u>the force tending to lift the load</u> off the ground (vertical force) is equal to <u>22.5N.</u>

Have a nice day!

8 0
4 years ago
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