(0, 0) → t = 0, w = 0 → w = 0 · 0
(1, 4) → t = 1, w = 4 → w = 1 · 4
(2, 8) → t = 2, w = 8 → w = 2 · 4
(3, 12) → t = 3, w = 12 → w = 3 · 4
<h3>Answer: w = 4t</h3>
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Literally y is across from 112, so y=112
Answer:
WORDS: The value of x is 15.
EQUATION: x = 15
Step-by-step explanation:
1. AB is a straight line therefore angles AOF, FOG, and GOB total 180º
2. If ∠FOG = 90º, AOF + GOB = 90º by subtraction & substitution property
3. 5x - 15 + 2x = 90 (now solve) --> by substitution
4. 7x - 15 = 90 --> by C.L.T. or <u>C</u>ombine <u>L</u>ike <u>T</u>erms
5. 7x = 105 --> by C.L.T. or <u>C</u>ombine <u>L</u>ike <u>T</u>erms
6. x = 15 --> by inverse operations (division)
Hope this helps!