a simple lifting machine consisting of a rope which unwinds from a wheel on to a cylindrical drum or shaft joined to the wheel to provide mechanical advantage. reeeeeeeeeeeeeeeeeeeeeeeeee
That would be
0 degrees Celsius aka the melting point of water.... If you look at the diagram I attached you notice that at 0 degrees Celsius it is flat, this is because much heat is needed at this point for water to rise to 1 degree... It is the same for the boiling point (100)<span />
Answer:
It's B
Explanation:
Hope this helps, tell me if im wrong!
Answer:
distance = 6.1022 x10^16[m]
Explanation:
To solve this problem we must use the formula of the average speed which relates distance to time, so we have
v = distance / time
where:
v = velocity = 3 x 10^8 [m/s]
distance = x [meters]
time = 6.45 [light years]
Now we have to convert from light-years to seconds in order to get the distance in meters.
![t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]](https://tex.z-dn.net/?f=t%20%3D%206.45%20%5Blight-years%5D%2A365%5B%5Cfrac%7Bdays%7D%7B1light-year%7D%5D%2A24%5B%5Cfrac%7Bhr%7D%7B1day%7D%5D%20%2A60%5B%5Cfrac%7Bmin%7D%7B1hr%7D%5D%2A60%5B%5Cfrac%7Bseg%7D%7B1min%7D%20%5D%20%3D203407200%20%5Bs%5D)
Now using the formula:
distance = v * time
distance = (3*10^8)*203407200
distance = 6.1022 x10^16[m]
Answer:
Follows are the solution to this question:
Explanation:
Please find the correct question in the attachment file.
Let:

Calculating the value of 
![\to \left | \begin{array}{ccc}\hat{i}&\hat{j}&\hat{K}\\R_i&R_j&R_k\\S_i&S_j&S_k\end{array}\right | = \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j]](https://tex.z-dn.net/?f=%5Cto%20%5Cleft%20%7C%20%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7BK%7D%5C%5CR_i%26R_j%26R_k%5C%5CS_i%26S_j%26S_k%5Cend%7Barray%7D%5Cright%20%7C%20%3D%20%5Chat%7Bi%7D%5BR_j%20S_k-S_jR_k%5D-%5Chat%7Bj%7D%5BR_i%20S_k-S_iR_k%5D%2B%5Chat%7Bk%7D%5BR_i%20S_j-S_iR_j%5D)
Calculating the value of 
![\to (R_i\hat{i}+R_j\hat{j}+R_k\hat{k}) \cdot ( \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j])](https://tex.z-dn.net/?f=%5Cto%20%28R_i%5Chat%7Bi%7D%2BR_j%5Chat%7Bj%7D%2BR_k%5Chat%7Bk%7D%29%20%5Ccdot%20%28%20%5Chat%7Bi%7D%5BR_j%20S_k-S_jR_k%5D-%5Chat%7Bj%7D%5BR_i%20S_k-S_iR_k%5D%2B%5Chat%7Bk%7D%5BR_i%20S_j-S_iR_j%5D%29)
by solving this value it is equal to 0.