<u>Answer:
</u>
Distance traveled = 70 meters
Displacement = 36.06 meters
<u>Explanation:
</u>
Let north be positive Y and east be positive X
10 meters north, displacement = 10 j meters
20 meters west, displacement = -20 i meters
40 meters south, displacement = -40 j meters
Total displacement = (10 j - 20 i – 40 j) meters = (- 20 i - 30 j) meters
Magnitude of displacement = 
Distance traveled = 10+20+40 = 70 meters
Using current technology, useful parallax measurements can only be found for stars up to about 340 light years (100 parsecs) away.
Answer:
largest lead = 3 m
Explanation:
Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.
So, first we need to calculate the velocities of both the anchorman
given data:
Distance = d = 100 m
Time arrival for A = 9.8 s
Time arrival for B = 10.1 s
Velocity of anchorman A = D / Time arrival for A
=100/ 9.8 = 10.2 m/s
Velocity of anchorman B = D / Time arrival for B
=100/10.1 = 9.9 m/s
As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use
d = vt
= 9.9 x 9.8 = 97 m
So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.
largest lead = 100 - 97 = 3 m
So if his lead no more than 3 m anchorman A win the race.
