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3 years ago

After which action would the concentration of a solution remain constant?(1 point)

Physics

1 answer:

Alika [10]3 years ago

5 0

Answer:

C. Evaporating water from the container.

Explanation:

The concentration of solution changes when solvent or solute are added/removed from a solution.

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Which choice can be correctly defined as “the sum of all charge in a closed system remains constant”?

Elena-2011 [213]

Answer:

Law conservation of charge (D)

Explanation:

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3 years ago

Read 2 more answers

If the maximum energy given to an electron during compton scattering is 30 kev, what is the wavelength of the incident photon?

hammer [34]

The wavelength of the incident photon is $1.19x10^{-2} nm$ .

What is wavelength?

The wavelength, or the distance over which the shape of a periodic wave repeats, is the spatial period in physics. It is a property of both traveling waves and standing waves, as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two neighboring crests, troughs, or zero crossings. The Greek letter lambda is frequently used to denote wavelength. The term wavelength is also sometimes used to describe modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.

The relationship between wavelength and frequency is inverse, assuming a sinusoidal wave flowing at a constant speed.

Calculations:

The energy loss Δλ=h/ $m_{e} c$ (1-cos∅)

Conservation of momentum gives,

$h_{f} =P_{e} c-hf'\\hf+hf'=P_{e} c\\hf+hf'=\sqrt{(m_{e} c^{2} } +k^{2} )-me^{2} c^{4} \\\\=\sqrt {(511+30)^{2} -(511)^{2} } \\=178keV$

$hf=hf'+k=hf-hf'=30keV\\$

$2hf=178+30\\2hf=208\\hf=104keV\\$

Wavelength(λ)= $\frac{hc}{104keV}$ = $\frac{1.24keV.nm}{104keV}$

Wavelength(λ)= $1.19x10^{-2} nm$

To learn more about wavelength , visit:

brainly.com/question/12924624

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6 0

2 years ago

Performs Parts 1-3 in lab, Part 4 you answer by using your information gathered through Parts 1-3.

elena55 [62]

Oh okie oh gosh lol lol

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3 years ago

A block with mass m is pulled horizontally with a force F_pull leading to an acceleration a along a rough, flat surface.

Simora [160]

Answer:

$\mu_k=\frac{a}{g}$

Explanation:

The force of kinetic friction on the block is defined as:

$F_k=\mu_kN$

Where $\mu_k$ is the coefficient of kinetic friction between the block and the surface and N is the normal force, which is always perpendicular to the surface that the object contacts. So, according to the free body diagram of the block, we have:

$N=mg\\F_k=F=ma$

Replacing this in the first equation and solving for $\mu_k$ :

$ma=\mu_k(mg)\\\mu_k=\frac{a}{g}$

6 0

3 years ago

Angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes (the):

Vsevolod [243]

Angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes the line focus principle

<h3>What is the line focus principle?</h3>

The line focus principle states that as the anode angle is reduced, the actual focal spot also becomes small but the heat loading is increased.

It also explains the relationship between the anode surface and the effective focal spot size.

As a result of this, by angling the target, effective area of the target is made much smaller that the actual area of electron interaction.

Hence, angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes the line focus principle.

Learn more about line focus principle here:

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3 0

2 years ago