Answer:
stimulate hormone and stimulate the growth of follicle in the ovary with this growth
Which of the following<span> is </span>not supported<span> by the </span>endosymbiotic theory<span>? ... </span>ingested<span> the</span>smaller prokaryotes<span> in a </span>parasitic relationship<span>. </span>Ancient aerobic prokaryotes<span> that </span>lived<span> in </span>community inside other prokaryotes evolved into mitochondria<span>. </span>Ancient photosynthetic prokaryotes evolved into modern chloroplasts<span>.</span>
Answer:
All their descendants will be heterozygous for the skin color, Bb, expressing blue skin.
Explanation:
<u>Available data</u>:
- Smurfette has light blue skin
- Her family is a "true bred" or "purebred" line.
- She married a boy who has light yellow skin
- blue skin is the dominant trait expressed by the B allele
- yellow skin is a recessive trait, expressed by the b allele
Cross: Smurfette x Husband
Parentals) BB x bb
Gametes) B B b b
Phenotypes) blue skin yellow skin
Punnett square)
B B
b Bb Bb
b Bb Bb
F1) 100% of the progeny will be heterozygous for the skin color, Bb
100% of the progeny will be blue-skinned.
Note: Although the progeny is blue-skinned, they are not true-bred anymore.
Answer:
molecule regulates the fluidity of phospholipids
I think he would survive cus fish need water to survive so it could work as long as the fish had water :D
