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Gnesinka [82]
3 years ago
15

If the air temperature increased, with no addition or removal of water vapor, the actual vapor pressure would

Physics
1 answer:
frosja888 [35]3 years ago
6 0
It would increase--materials expand as they get hotter.
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Me ajudem, Por favor!!!!!!
zzz [600]

Answer:

a)  a=4\,\frac{m}{s^2}

b)  V(t)=4\,t\,+3

c)  V(1)=7 \,\frac{m}{s} \\

d)  Displacement = 22 m

e)  Average speed = 11 m/s

Explanation:

a)

Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:

slope= \frac{15=3}{3-0} =4\,\frac{m}{s^2}

Therefore,  acceleration is a=4\,\frac{m}{s^2}

b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:

y=m\,x+b\\V(t)=4\,t\,+3

c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:

V(t)= 4\,t+3\\V(1)=4\,(1)+3\\V(1)=7 \,\frac{m}{s}

d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):

Displacement = \frac{(7+15)\,2}{2} = 22\,\,m

e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:

Average velocity = \frac{22}{2} = 11\, \,\frac{m}{s}

3 0
4 years ago
Puck 1 (0.5 kg) travels with velocity 20 m/s to the right when it collides with puck 2 (2 kg) which is initially at rest. After
Vinvika [58]

Answer:

The final velocity of puck 2 is 6 m/s to the right

Explanation:

Given;

mass of puck 1, m₁ = 0.5 kg

mass of puck 2, m₂ = 2 kg

initial velocity of puck 1, u₁ = 20 m/s

initial velocity of puck 1, u₂ = 0

final velocity of puck 1, v₁ = -4 m/s

Let the final velocity of puck 2 = v₂

Applying the principle of conservation linear momentum, total momentum before collision is equal to total momentum after collision.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.5 x 20) + (2 x 0) = (0.5 x -4) + 2v₂

10 = -2 + 2v₂

2v₂ = 12

v₂ = 12/2

v₂ = 6 m/s

This positive final velocity of puck 2, indicates that it moved to the right.

8 0
3 years ago
With what speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?
11Alexandr11 [23.1K]
Velocity =2 pie*r/t
distance = 2 (pie) r
accelaretion =distance/t2
f=m*v2/r
v=square root of Fr/m

5 0
4 years ago
I need help with question 17
Alexxx [7]
It is b i had that qustion 

6 0
3 years ago
!!!! pleaseee helppp!!!!
aleksandrvk [35]
YES I WILL HELP YOU SO MUCH
5 0
3 years ago
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