Answer:
a) 
b) 
c) 
d) Displacement = 22 m
e) Average speed = 11 m/s
Explanation:
a)
Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:

Therefore, acceleration is 
b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:

c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:

d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):
Displacement = 
e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:
Average velocity = 
Answer:
The final velocity of puck 2 is 6 m/s to the right
Explanation:
Given;
mass of puck 1, m₁ = 0.5 kg
mass of puck 2, m₂ = 2 kg
initial velocity of puck 1, u₁ = 20 m/s
initial velocity of puck 1, u₂ = 0
final velocity of puck 1, v₁ = -4 m/s
Let the final velocity of puck 2 = v₂
Applying the principle of conservation linear momentum, total momentum before collision is equal to total momentum after collision.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(0.5 x 20) + (2 x 0) = (0.5 x -4) + 2v₂
10 = -2 + 2v₂
2v₂ = 12
v₂ = 12/2
v₂ = 6 m/s
This positive final velocity of puck 2, indicates that it moved to the right.
Velocity =2 pie*r/t
distance = 2 (pie) r
accelaretion =distance/t2
f=m*v2/r
v=square root of Fr/m
It is b i had that qustion
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