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aleksley [76]
4 years ago
10

With what speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?

Physics
1 answer:
11Alexandr11 [23.1K]4 years ago
5 0
Velocity =2 pie*r/t
distance = 2 (pie) r
accelaretion =distance/t2
f=m*v2/r
v=square root of Fr/m

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Answer:

1.19 m/s²

Explanation:

The frequency of the wave generated in the string in the first experiment is f = n/2l√T/μ were T = tension in string = mg were m = 1.30 kg weight = 1300 g , μ = mass per unit length of string = 1.01 g/m. l = length of string to pulley = l₀/2 were l₀ = lent of string. Since f is the second harmonic, n = 2, so

f = 2/2(l₀/2)√mg/μ = 2(√mg/μ)/l₀    (1)

Also, for the second experiment, the period of the wave in the string is T = 2π√l₀/g. From (1) l₀ = 2(√mg/μ)/f and from (2) l₀ = T²g/4π²

Equating (1) and (2) we ave

2(√mg/μ)/f = T²g/4π²

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g = 2π√(2√(m/μ)/f)/T

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g = 1.19 m/s²

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