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tester [92]
2 years ago
11

A boy is swinging a yo-yo with mass 0.5 kg in a circle with radius 0.7 m at a

Physics
1 answer:
Free_Kalibri [48]2 years ago
6 0

Based on the calculations, the tension in the string connecting the yo-yo to the boy's finger is equal to: A. 35 Newton.

<u>Given the following data:</u>

  • Mass, m = 0.5 kg.
  • Speed, v = 7 m/s.
  • Radius, r = 0.7 meters.

<h3>How to calculate the tension in this string?</h3>

Based on the information provided, we can logically deduce that the tension in the string connecting the yo-yo to the boy's finger is equal to the centripetal force acting on it.

Mathematically, centripetal force can be calculated by using this formula:

Fc = mv²/r

Fc = (0.5 × 7²)/0.7

Fc = 24.5/0.7

Fc = 35 Newton.

Read more on force here: brainly.com/question/12570594

#SPJ1

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two charges having the same charge magnitude experiencing an attracting force of 3.60N when the charges are 30cm apart.what is t
Tomtit [17]

The charges have opposite sign and magnitude 6 \mu C

Explanation:

The magnitude of the electrostatic force between two electric charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

In this problem, we have:

F = 3.60 N is the force between the two charges

r = 30 cm = 0.30 m is their separation

The two charges have same magnitude, so

q_1 = q_2 = q

So we can rewrite the equation as

F=\frac{kq^2}{r^2}

And solving for q:

q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(3.60)(0.30)^2}{8.99\cdot 10^9}}=6\cdot 10^{-6} C = 6\mu C

Moreover, the force between the charges is attractive: we know that charges of same sign repel each other while charges of opposite sign attract each other, therefore the charges in this problem have opposite sign, so

q_1 = 6 \mu C\\q_2 = -6 \mu C

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brainly.com/question/8960054

brainly.com/question/4273177

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3 0
3 years ago
George is applying a downward force of 50N to and object that has a mass of 50kg. What is the normal force (FN) of the object wh
attashe74 [19]

The normal force acting on the object is 500 N in the upward direction

<u>Explanation:</u>

As George is applying a downward force, the normal force will be in the upward direction. The normal force will be exerted due to the acceleration due to gravity exerted on the object.

So, as per Newton's second law, the normal force acting on the object can be measured by the product of mass of the object and the acceleration due to gravity acting on the object.

But as the acceleration due to gravity is a downward acting acceleration and the normal force is a upward acting force, so the acceleration will be having a negative sign in the formula.

Normal\ force = Mass \times Acceleration\ due\ to\ gravity

Here, acceleration due to gravity g = -10 m/s² and mass is given as 50 kg, then

Normal force = 50 × (-10) = -500 N

So, the normal force acting on the object is 500 N in the upward direction.

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3 years ago
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kolezko [41]

Entropy is the measure of the amount of disordered in a system.

<u>Explanation:</u>

In 1850, Entropy introduction by the German physicist Rudolf Clausius refers a measurement of the system's thermal energy in unit temperature. It is not for useful work because the work originates from ordered molecular motions. And, this also measures the molecular disturbance or randomness of the system.

The concept behind this provides deep view into spontaneous changes in many everyday phenomena’s. The idea of entropy is a mathematical way of coding an intuitive idea whose processes are impossible, and not violate the basic principle of energy conservation.

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Answer:

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