<u>The answer to your question is going to be option "D."</u>
Oxygen levels first rose in the atmosphere because of (the last option, or "D') cyanobacteria. Cyanobacteria is a type of bacteria that can create toxins that are very dangerous to both humans and animals.
I hope this helps! :)
Anwser
For general projectile motion with no air resistance, the horizontal component of a projectile's velocity ... D. first decreases and then increases ... E. The speed of the object is constant but its velocity is not constant. C ... Neglecting air resistance, when the package hits the ground
Explanation:
Pressure = Force / Area
Put your data in front of yourself.
Force = 600 Newtons
Area = 300 cm^2
Firstly you need to convert the area into m^2 and you do this by diving 300 with 10000.
Now you use the formula:-
Pressure = 600/ 0.03
Which comes out to be 20,000 Pa.
Hope this helps!
Answer:
The position and velocity of the spring is −2.12 inches and -6.66 ft/s.
Explanation:
Given that,
The position function,
![s(t)=-3\cos(\pi t+\dfrac{\pi}{4})](https://tex.z-dn.net/?f=s%28t%29%3D-3%5Ccos%28%5Cpi%20t%2B%5Cdfrac%7B%5Cpi%7D%7B4%7D%29)
We need to calculate the position of the spring at t = 1.5 s
Using position function
![s(t)=-3\cos(\pi t+\dfrac{\pi}{4})](https://tex.z-dn.net/?f=s%28t%29%3D-3%5Ccos%28%5Cpi%20t%2B%5Cdfrac%7B%5Cpi%7D%7B4%7D%29)
Put the value of t in the function
![s(1.5)=-3\cos(\pi\times1.5+\dfrac{\pi}{4})](https://tex.z-dn.net/?f=s%281.5%29%3D-3%5Ccos%28%5Cpi%5Ctimes1.5%2B%5Cdfrac%7B%5Cpi%7D%7B4%7D%29)
![s(1.5)=-2.12\ inches](https://tex.z-dn.net/?f=s%281.5%29%3D-2.12%5C%20inches)
We need to calculate the velocity of the spring
Using position function
![s(t)=-3\cos(\pi t+\dfrac{\pi}{4})](https://tex.z-dn.net/?f=s%28t%29%3D-3%5Ccos%28%5Cpi%20t%2B%5Cdfrac%7B%5Cpi%7D%7B4%7D%29)
On differentiating
![\dfrac{ds}{dt}=3\pi\sin(\pi t+\dfrac{\pi}{4})](https://tex.z-dn.net/?f=%5Cdfrac%7Bds%7D%7Bdt%7D%3D3%5Cpi%5Csin%28%5Cpi%20t%2B%5Cdfrac%7B%5Cpi%7D%7B4%7D%29)
![v(t)=3\pi\sin(\pi t+\dfrac{\pi}{4})](https://tex.z-dn.net/?f=v%28t%29%3D3%5Cpi%5Csin%28%5Cpi%20t%2B%5Cdfrac%7B%5Cpi%7D%7B4%7D%29)
Put the value into the formula
![v(1.5)=3\pi\sin(1.5\pi+\dfrac{\pi}{4})](https://tex.z-dn.net/?f=v%281.5%29%3D3%5Cpi%5Csin%281.5%5Cpi%2B%5Cdfrac%7B%5Cpi%7D%7B4%7D%29)
![v(1.5)=-6.66\ ft/sec](https://tex.z-dn.net/?f=v%281.5%29%3D-6.66%5C%20ft%2Fsec)
Hence, The position and velocity of the spring is −2.12 inches and -6.66 ft/s.
Answer:
the water level was shallow beach, then it rose to deep sea, then the water receded to a beach