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3 years ago

When you set something down on the ground what kind of work is your arm doing

Physics

2 answers:

Ksju [112]3 years ago

7 0

When you set something down, gravity does positive work, while YOU do negative work.

Zigmanuir [339]3 years ago

5 0

I think it would be negative apex :)

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it is about 384,750 kilometers from earth to the moon. it took the apollo astronauts about 2 days and 19.5 hours to fly to the m

Jet001 [13]

We know, speed = Distance / Time
d = 384,750 Km
t = 2 days, 19.5 hours = 48+19.5 = 67.5 hour

Substitute their values,
s = 384,750 / 67.5
s = 5700 Km/h

In short, Your Answer would be 5700 Km/h

Hope this helps!

7 0

3 years ago

Read 2 more answers

Does electrons have more mass than neutrons?

musickatia [10]

Answer:

No, neutrons have about the same mass as a proton, but both have more mass than electrons.

Hope this helps a bit,

Flips

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3 years ago

Thermal escape of an atmosphere is most pronounced on worlds where the gravity is low and the temperature is high.

Alona [7]

The answer is false

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3 years ago

The wave function of a particle is exp(i(kx-omegat)), where x is distance, t is time, and k and co are positive real numbers. Th

Step2247 [10]

Answer:

Momentum, $p=\hbar k$

Explanation:

The wave function of a particle is given by :

$y=exp[i(kx-\omega t)]$ ...............(1)

Where

x is the distance travelled

t is the time taken

k is the propagation constant

$\omega$ is the angular frequency

The relation between the momentum and wavelength is given by :

$p=\dfrac{h}{\lambda}$ ............(2)

From equation (1),

$k=\dfrac{2\pi}{\lambda}$

$\lambda=\dfrac{2\pi}{k}$

Use above equation in equation (2) as :

$p=\dfrac{h k}{2\pi }$

Since, $\dfrac{h}{2\pi}=\hbar$

$p=\hbar k$

So, the x-component of the momentum of the particle is $\hbar k$ . Hence, this is the required solution.

8 0

3 years ago

Each of the following diagrams shows a spaceship somewhere along the way between Earth and the Moon (not to scale); the midpoint

djyliett [7]

Answer:

$F_5 >F_4>F_1 >F_2>F_3$

Where $F_i$ represent the force for each of the 5 cases $i -1,2,3,4,5$ presented on the figure attached.

Explanation:

For this case the figure attached shows the illustration for the problem

We have an inverse square law with distance for the force, so then the force of gravity between Earth and the spaceship is lower when the spaceship is far away from Earth.

Th formula is given by:

$F = G \frac{m_{Earth} m_{Spaceship}}{r^2}$

Where G is a constant $G = 6.674 x10^{-11} m^2/ (ks s^2)$

$m_{Earth}$ represent the mass for the earth

$m_{spaceship}$ represent the mass for the spaceship

$r$ represent the radius between the earth and the spaceship

For this reason when the distance between the Earth and the Spaceship increases the Force of gravity needs to decrease since are inversely proportional the force and the radius, and for the other case when the Earth and the spaceship are near then the radius decrease and the Force increase.

Based on this case we can create the following rank:

$F_5 >F_4>F_1 >F_2>F_3$

Where $F_i$ represent the force for each of the 5 cases $i -1,2,3,4,5$ presented on the figure attached.

6 0

3 years ago