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3 years ago

12

. At what velocity will the box in Problem 6 be traveling when it hits the ground? Use formula: Va = Vf - Vi / 2

1 answer:

VladimirAG [237]3 years ago

5 0

Answer:

How much time does his victim on the ground below have to move out of harm's way? At what velocity will the safe hit the ground? sownt d-200m. n a = 100/2. Vi-o.

Explanation:

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Your electric drill rotates initially at 5.21 rad/s. You slide the speed control and cause the drill to undergo constant angular

RUDIKE [14]

Answer:

The drill's angular displacement during that time interval is 24.17 rad.

Explanation:

Given;

initial angular velocity of the electric drill, $\omega _i$ = 5.21 rad/s

angular acceleration of the electric drill, α = 0.311 rad/s²

time of motion of the electric drill, t = 4.13 s

The angular displacement of the electric drill at the given time interval is calculated as;

$\theta = \omega _i t \ + \ \frac{1}{2}\alpha t^2\\\\\theta = (5.21 \ \times \ 4.13) \ + \ \frac{1}{2}(0.311)(4.13)^2\\\\\theta = (21.5173 ) \ + \ (2.6524)\\\\\theta =24.17 \ rad$

Therefore, the drill's angular displacement during that time interval is 24.17 rad.

6 0

3 years ago

a 3,000kg truck runs into the rear of a 1000kg car that was stationary. The truck and car are locked together after the collisio

joja [24]

FVJDJFN.s<ldF KN,M c":F,BJ TNHIJRT IHJYODIFG

7 0

3 years ago

A school bus is headed on a field trip to LA traveling at 55 mph. Robert is

Scorpion4ik [409]

Answer: 63 miles per hour

i think

Explanation:

6 0

3 years ago

A 25 kg block is held against a compressed spring and then the spring is allowed to decompress giving the block a velocity. The

Alex787 [66]

Answer:

h=18.05 cm

Explanation:

Given that

m= 25 kg

K= 1300 N/m

x=26.4 cm

θ= 19.5 ∘

When the block just leave the spring then the speed of block = v m/s

From energy conservation

$\dfrac{1}{2}Kx^2=\dfrac{1}{2}mv^2$

$Kx^2=mv^2$

$v=\sqrt{\dfrac{kx^2}{m}}$

By putting the values

$v=\sqrt{\dfrac{kx^2}{m}}$

$v=\sqrt{\dfrac{1300\times 0.264^2}{25}}$

v=1.9 m/s

When block reach at the maximum height(h) position then the final speed of the block will be zero.

We know that

$V_f^2=V_i^2-2gh$

By putting the values

$0^2=1.9^2-2\times 10\times h$

h=0.1805 m

h=18.05 cm

4 0

3 years ago

What happens to the reaction 2 N O 2 in equilibrium with N 2 O 4 plus 57.3 kilojoules when the temperature of the reaction is in

Burka [1]

Answer:

More reactant forms.

Explanation:

Given reaction is,

$2NO_{2}$ ⇒ $N_{2} O_{4}+57.3 KiloJoules$ per mole

This is an Exothermic Reaction,(ΔE=-57.3KJper mole)

We know the equilibrium point of all Exothermic reactions moves leftward and more reactant is formed at the equilibrium.

<u>Reason:</u>

As heat is being produced in the reaction the additional heat(57.3KJpermole) can be <u>thought of as a product</u> of the reaction.

So,if you increase the temperature ,you provide heat energy,

(in other words heat energy is given) and hence the concentration of the products increases.

So, with respect to LeChateliers Principle,

As the concentration of products is increased by external means,more of the reactants are produced at the equilibrium of the reaction.

Therefore amount of reactants increases as <u>more reactant forms.</u>

3 0

3 years ago

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