Answer:
Time taken for trip = 12.74 hour (Approx)
Explanation:
Given:
Distance of trip = 710-mi
Average speed for the trip = 55.7 mi/h
Find:
Time taken for trip = ?
Computation:
⇒ Time = Distance / Speed
⇒ Time taken for trip = Distance of trip / Average speed for the trip
⇒ Time taken for trip = 710-mi / 55.7 mi/h
⇒ Time taken for trip = 12.74 hour (Approx)
Yes, atoms need to be equal in protons and electrons
An atom. Hope this helped
B is the answer
16 x 6.0 = 96
Helping is my pleasure
<h2>Hello!</h2>
The answer is: 19.59 m
<h2>Why?</h2>
Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.
When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:
We will use the following formula:
![Vf^2=Vi^2+2*g*s](https://tex.z-dn.net/?f=Vf%5E2%3DVi%5E2%2B2%2Ag%2As)
Where:
Vf= Final velocity = 0
Vi= Initial velocity = ![\frac{19.6m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7B19.6m%7D%7Bs%7D)
g = Gravity Acceleration = ![\frac{9.81m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B9.81m%7D%7Bs%5E%7B2%7D%20%7D)
s = Traveled distance
![0=19.6^2+2*-9.81*s\\s=\frac{19.6^2}{2*9.81}=\frac{384.16}{19.62}=19.59m](https://tex.z-dn.net/?f=0%3D19.6%5E2%2B2%2A-9.81%2As%5C%5Cs%3D%5Cfrac%7B19.6%5E2%7D%7B2%2A9.81%7D%3D%5Cfrac%7B384.16%7D%7B19.62%7D%3D19.59m)
Have a nice day!