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lapo4ka [179]
3 years ago
12

Suppose you look at the huge clock on the Big Ben Tower in London and it reads 12 noon. If you could travel away from the clock

at the speed of light and view it with a telescope, it would: A. run slower than usual
B. run faster than usual
C. be frozen at 12 noon
D. running backwards
Physics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

Option C. be frozen at 12 noon

Explanation:

This can be explained by the special theory of relativity according to which at greater speeds time slows down and length contracts in the direction of motion.

Also if a body travels at the speed of light time will stop and the body will will reduce to zero length.

Therefore, for the given case time will freeze at 12 noon.

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Your spaceship lands on an unknown planet. to determine the characteristics of this planet, you drop a 1.50 kg wrench from 5.50
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1. calculate the value of acceleration that objects gains in that period of time
•calculating acceleration
5.50 = 1/2at^2
5.50*2/t^2 = a
11.00/0.657 = a
16.74=a
now you got the acceleration
2. you have laws of gravitation for that

g = Gm/r^2
where g is the acceleration value
16.74 = 6.754*10^-11 × m/ 6.28*10^4
105.14*10^4 /6.754*10-11 = m
15.567*10^15 = m
that would be the mass of the planet ...
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What comes first the color orange or the fruit orange
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Answer:

Given the exoticism of the orange fruit, you could be forgiven that the color came first as it naturally occurs independent of the fruit such as in sunsets or leaves in autumn. Orange actually comes from the Old French word for the citrus fruit - 'pomme d'orenge' - according to the Collins dictionary.

Explanation:

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3 years ago
An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pip
OverLord2011 [107]

Answer:

The value is v_2 =  5.53 \  m /s

Explanation:

From the question we are told

  The pipe diameter at location 1 is  d  = 8.8 \  cm =  \frac{8.8 }{10} = 0.88 \ m

   The velocity at location 1 is  v_1 =  2.4 \  m /s

   The diameter at location 2 is  d_2 =  5.80 \  cm  =  0.58 \  m

Generally the area at location 1 is  

       A_1 =  \pi *  \frac{d^2}{ 2}

=>     A_1 =  \pi *  \frac{0.88^2}{ 2}

=>     A_1 = 3.142 *  \frac{0.88^2}{ 2}

=>     A_1 = 1.2166 \  m^2

Generally the area at location 1 is  

       A_2 =  \pi *  \frac{d_1^2}{ 2}

=>     A_2 =  \pi *  \frac{0.58^2}{ 2}

=>     A_2 = 0.528  \  m^2

Generally from continuity equation we have that

     A_1 * v_1 =  A_2 * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>    v_2 =  5.53 \  m /s

3 0
3 years ago
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