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Igoryamba
3 years ago
6

A tank 20 m deep and 7m wide is layered with 8m of oil,6m of water and 5m of mercury.complete total hydroatatic force.(density o

f oil and mercury is 800 and 13600kg/m respectively ).​
Physics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

F = 3.03 10⁷ N

Explanation:

We will eat by calculating the pressure in the tank

         P = ρ g h

the pressure totals the sum of the pressure of each liquid

       P_total = P_oil + P_water + P_Hg

       P_total = ρ_oil ​​g h_oil + ρ_water g h_water + ρ_Hg g h_Hg

       P_total = g (ρ_oil ​​h_oil + ρ_water h_water + ρ_Hg h_Hg)

       P_total = 9.8 (800 8 + 1000 6 + 13 600 5)

        P_total = 7,879 10⁵ Pa

The definition of Pressure is

       P = F / A

        F = P A

The area of ​​a tank is the area of ​​a circle

       A = π r² = π d² / 4

       

      F = P π d² / 4

let's calculate

      F = 7,879 10⁵ π 7²/4

      F = 3.03 10⁷ N

In this calculation the atmospheric pressure was not taken into account because they ask the hydrostatic pressure

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Answer:

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Explanation:

Givens

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The wave length is defined as \lambda = 2L = 2(0.95m)=1.9m

Now, to find the speed, we need the tension of the wire and its linear mass density

v=\sqrt{\frac{T}{\mu} }

Where \mu=\frac{0.005kg}{0.95m}= 5.26 \times 10^{-3} and the tension is defined as T=m_{sculpture} g=13kg(9.81 m/s^{2} )=127.53N

Replacing this value, the speed is

v=\sqrt{\frac{127.53N}{5.26 \times 10^{-3} } }=155.71 m/s

Then, we replace the speed and the wave length in the first equation

f=\frac{v}{\lambda}\\f=\frac{155.71 m/s}{1.9m}\\ f=81.96Hz

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Explanation:

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