Given:
mass: 100 kg
height: 500 m
1 kJ = 1000 J
gravity = 9.8 m/s²
velocity before impact: v = √2gh ; v = √2 * 9.8 m/s² * 500 m ; v = 98.99494 m/s
KE = 1/2 m v²
KE = 1/2 * 100 kg * (98.99494 m/s)²
KE = 490,000 J
Pls. see attachment.
Nitrogen isotopes don't have a charge.
Answer:
18 km
Explanation:
Convert km/h to m/s:
120 km/h × (1000 m/km) × (1 h / 3600 s) = 33.3 m/s
The time it takes the bomb to travel the 2000 meters is:
2000 m / (33.3 m/s) = 60 s
So it takes 60 seconds for the bomb to fall. The distance it fell is therefore:
Δy = v₀ᵧ t + ½ aᵧ t²
Δy = (0 m/s) (60 s) + ½ (10 m/s²) (60 s)²
Δy = 18,000 m
Δy = 18 km