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nikklg [1K]
3 years ago
6

Calculate the potential energy of a 5 kg object sitting at the top of a 2 meter ramp.

Physics
1 answer:
trapecia [35]3 years ago
5 0
The formula used to find potential energy is <em>P.E. = M * G * H</em> (P.E. is potential energy, M is mass, G is gravitational pull, and H is height). So the answer to your question is <em>5 * 9.8 * 2</em>, which equals 98.
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A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 5.0 km/h
Ratling [72]

Answer

given,

time  = 10 s

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F = m a

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In the first case

F₁=m x a₁

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F₁ is constant acceleration is also a constant.

Δv₁ = 5 x 0.278

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a₃ = 0.5282 m²/s

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a₃ = a₂ + a₁

0.5282 = a₂ + 0.139

a₂=0.3892 m²/s

F₂ = m x 0.3892...........(1)

F₁ = m x 0.139...............(2)

F₂/F₁

ratio = \dfrac{0.3892}{0.139}

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6 0
3 years ago
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Answer:

6.5454 m

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\frac{\mu _0i_1}{2\pi x}=\frac{\mu _0i_2}{2\pi (24-x)}

Here i_1=3\ A \ and\  i_2=8\ A

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