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nikklg [1K]
3 years ago
6

Calculate the potential energy of a 5 kg object sitting at the top of a 2 meter ramp.

Physics
1 answer:
trapecia [35]3 years ago
5 0
The formula used to find potential energy is <em>P.E. = M * G * H</em> (P.E. is potential energy, M is mass, G is gravitational pull, and H is height). So the answer to your question is <em>5 * 9.8 * 2</em>, which equals 98.
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5.
SVETLANKA909090 [29]

Answer: black

Explanation: When green light is shone on a red object, it absorbs all of the green light and not reflecting anything. Hence, it appears black.

8 0
3 years ago
A faulty thermometer reads 2°C when dipped in ice at 0°C and 95°C when dipped in steam at 100°C. What would this thermometer rea
kvasek [131]

Answer:

The read will be 20.9[C]x=\frac{(y-y_{1} )}{(y_{2} -y_{1} )}*(x_{2}-x_{1})+y_{1}\\  x=\frac{(18-0 )}{(95 -0 )}*(100-2)+2\\\\x= 20.9[C]

Explanation:

This is a problem related to linear interpolation, Linear interpolation consists of tracing a line through two known points y = r (x) and calculating the intermediate values according to this line.

The equation of a known line two points (x1, y1)and (x2, y2) = (2,0) (100,95) is:

\frac{(y-y_{1} )}{(y_{2} -y_{1} )}=\frac{(x-y_{1} )}{(x_{2}-x_{1}  )}

If we clear y from the equation we have:

[tex]y=\frac{(x-y_{1})}{(x_{2}-x_{1} )}*(y_{2} -y_{1} )+y_{1}  \\replacing

4 0
3 years ago
When you throw a pebble straight up with initial speed V, it reaches a maximum height H with no air resistance. At what speed sh
aev [14]

Answer:

Explanation:

Given

Initial speed is u=V

Maximum height of Pebble is H

Deriving maximum height of Pebble and considering motion in vertical direction

v^2-u^2=2 as

where v=final velocity

u=initial velocity

a=acceleration

s=Displacement

Final velocity will be zero at maximum height

0-(V)^2=2\times (-g)\cdot H

H=\frac{V^2}{2g}

i.e. maximum height is dependent on square of initial velocity

for twice the height

2H=\frac{(V')^2}{2g}

on comparing

V'=\sqrt{2}V

7 0
3 years ago
A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how h
Aloiza [94]
v_x=16,9\frac{m}{s}\\&#10;s=44m\\&#10;g=10\frac{m}{s^2}\\\\&#10;v_x=\frac{s}{t}\Rightarrow t=\frac{s}{v_x}\\\\&#10;t=\frac{44}{16,9}\\\\&#10;t=2,6s\\\\&#10;h=\frac{gt^2}{2}\\\\&#10;h=\frac{10*2,6^2}{2}\\\\&#10;h=5*6,76\\\\&#10;h=33,8m
6 0
4 years ago
How many mL are in a cubic centimeter?
Furkat [3]
None of the above. 1 mL= 1 cubic centimeter
mm is the smallest.
4 0
3 years ago
Read 2 more answers
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