Answer: B, increase the rate at which he turns the crank
Explanation: i got it right
Answer:
The answer is based on the conservation of energy law; something you should really understand by now.
For convenience we can hold one of the two charges still; it becomes the frame of reference. And everything we say is in reference to the designated static charge, call it Q.
So the moving charge, call it q, has total energy TE = PE. It's all potential energy as we start with q not moving.
It has potential energy because in order to separate q from Q, we had to do work, add energy, on q. And from the COE law, that work added is converted into PE.
It's a bit like lifting something off the ground. That's work and it becomes GPE. So there's some work, in separating the two charges in the first place.
But there's more.
Now we let q go. As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.
And there's more work, done by the EMF on charge q. That converts the PE into KE and the q charge smashes into Q with some kinetic energy.
-- We already know the rate of revolutions per time ...
it's 1 revolution per 0.065 sec. We just have to
unit-convert that to 'per minute'.
(1 rev / 0.065 sec) x (60 sec / min) = (1 x 60) / (0.065) = <em>923 RPM</em> (rounded)
_______________________________
-- 1 revolution = 2π radians
(2π rad) / (0.065 sec) = (2π / 0.065) = <em>96.66 rad/sec</em> (rounded)
Answer:
a)COP = 1.67
b) W = 300 J
Explanation:
given,
refrigerator removes = 500 J from a cold reservoir
discharge = 800 J to its hot reservoir
a) COP = 
COP = 
COP = 1.67
b) heat per cycle exhausted to the
W + 500 = 800
W = 800- 500
W = 300 J
The tension, T, in each rope is T= mg/2Sinθ
<h3>What is tension force?</h3>
Tension refers to the pulling force in a string which acts in an opposite direction to the force pulling on it.
The tension in each of the ropes are equal since they both make the same angle with the vertical.
Assume the angle the ropes make with the vertical are both θ.
Let the tension in each be T₁ and T₂
Also, T₁ = T₂ = T
T₁Sinθ + T₂Sinθ = mg
2TSinθ = mg
T = mg/2Sinθ
Therefore, the tension, T, in each rope is T = mg/2Sinθ
Learn more about tension at: brainly.com/question/14336853
#SPJ4
