Answer:
The correct answer is option A: they are isotopes.
Explanation:
From atom X we know that the number of protons is 7 and the number of neutrons is 7 and from atom Z we know that the number of protons is 7 and the number of neutrons is 8.
Since the number of protons of atom X and atom Z is the same, we have that atom X and atom Z is the same element. The difference in the number of neutrons tells us that atom X and atom Z are isotopes. Remember that an isotope is one element that has atoms with different numbers of neutrons.
The mass number is given by:
Where <em>n</em> is the number of neutrons and <em>p </em>is the number of protons.
For atom X and atom Z we have:
Hence, they have a different mass number.
We know that the element with 7 protons is nitrogen. The first isotope is and the second isotope is
. Both isotopes are stables (they are not radioactive).
Therefore, the correct answer is option A: they are isotopes.
I hope it helps you!
Answer:
r₂=0.1 m
Explanation:
Given that
r₁= 10 m , β₁ = 20 dB
At r₂ ,β₂= 60 dB
As we know that intensity level of sound given as
10² x 10⁻¹² = I₁
I₁=10⁻¹⁰ W/m²
10⁶ x 10⁻¹² = I₂
I₂ = 10⁻⁶ W/m²
I₁=10⁻¹⁰ W/m²
P = I A
P=Power ,I =Intensity ,A=Area
r₂=0.1 m
To solve this problem we will apply the concepts related to kinetic energy and energy conservation. The kinetic energy will be expressed in terms of mass and speed, as well as load and voltage. From this last expression we will find the charges by electron and by Helium nucleus.
a ) Kinetic Energy is given as
Replacing with our values we have that
Therefore the kinetic energy of the helium nucleus is
PART B) Now for calculate the electron volts we use the kinetic energy as a expression between the charge and the voltage, that is
Here,
q = Charge of an electron
V = Voltage
Rearranging to find the potential we have,
Therefore the kinetic energy in electron vols is
PART C) Applying the same relationship but now using the Helium core load, we will have to
Here,
Q = Charge of a helium nucleus
V = Voltage
Rearranging to find the potential we have
But we need to note that the charge is equal to the number of charge for the unit charge, then
Now replacing we have that
Therefore the voltage applied is 371875V
Answer:
The value of the angle is .
Explanation:
Given:
The condition for diffraction minima is
where, is the slit-width,
is the angle of incidence,
is the order number and
is the wavelength of the light.
The wavelength of an electron traveling through a medium is governed by de Broglie's hypothesis.
According to de Broglie's hypothesis
Here, is Planck's constant,
is the mass of the electron and
is the velocity of the electron.
For first minimum .
From equation (1), we have