Answer:
The velocity in the water tunnel is 128.717m/s
Explanation:
To find the result we need to Apply dynamic symiliraty, that is,
Where is the kinematic viscosity, V the velocity and I the lenght.
To find the kinematic viscosity it is necessary search in the table with this properties (I attached it)
To this kind of fluids, the properties to 15.6°c (Seawater) and 20°c (Water)are:
(Seawater)
(Water)
Replacing,
Solving to V_m
The velocity in the water tunnel is 128.717m/s
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Answer:
Given,
load=300N
Load Distance=40 cm
Effort Distance = 60 cm
Formula used,
Load × load distance = Effort × effort distance
Effort = load × load distance/ effort distance
M.A=load/effort
V.R=effort distance/load distance
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