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pshichka [43]
3 years ago
9

Suppose that we repeat the experiment, except that we place the sodium flame in a strong, localized electric field. The field ch

anges the energy levels of the sodium atom, but it does not affect the sodium in the lamp or the photons it produces. The shadow cast by the sodium flame when illuminated by the sodium lamp should Stay the same, get darker, or lighter?
Physics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

Lighter

Explanation:

In practice, the lamp is powered by an AC voltage source which is connected in series with an inductive ballast in order to supply an approximately constant current to the lamp, rather than a constant voltage. This helps to provide a stable operation. The ballast is usually inductive rather than simply being resistive to maximize resistive losses.

As this lamp current tending to zero-current point and shadow cast by the sodium flame becoming lighter.  

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The movement of the tectonic plates is caused by convection currents in Earth´s mantle.

Answer: A) convection currents in Earth´s mantle.
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A water pump pumps 3 kg of water every second from the bottom of a well to the top of the well 50 m above if the pump used 2000
vesna_86 [32]

watts = work per second.

work is mgh = 3x10x50=1500

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eff=1500/2000=75%


8 0
3 years ago
One end of a 7-cm-long spring is attached to the ceiling. When a 5.4 kg mass is hung from the other end, the spring is stretched
mash [69]

Answer:

2.63 cm

Explanation:

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Making c the subject of the formula then

c=\frac {F}{y}

Since F is gm but taking the given mass to be F

c=\frac {5.4 kg}{4.3 cm}=1.2558139534883720930232558139534883720930

By substitution now considering F to be 3.3 kg

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8 0
3 years ago
Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat
Alja [10]

Answer:

Explanation:

Given that, the distance between the electrode is d.

The electron kinetic energy is Ek when the electrode are at distance "d" apart.

So, we want to find the K.E when that are at d/3 distance apart.

K.E = ½mv²

Note: the mass doesn't change, it is only the velocity that change.

Also,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Let assume that if is constant acceleration

Then, m and a is constant,

Then,

K.E is directly proportional to d

So, as d increase K.E increase and as d decreases K.E decreases.

So,

K.E_1 / d_1 = K.E_2 / d_2

K.E_1 = E_k

d_1 = d

d_2 = d/3

K.E_2 = K.E_1 / d_1 × d_2

K.E_2 = E_k × ⅓d / d

Then,

K.E_2 = ⅓E_k

So, the new kinetic energy is one third of the E_k

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3 years ago
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I think it’s b... not sure tho sorry
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