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pshichka [43]
3 years ago
9

Suppose that we repeat the experiment, except that we place the sodium flame in a strong, localized electric field. The field ch

anges the energy levels of the sodium atom, but it does not affect the sodium in the lamp or the photons it produces. The shadow cast by the sodium flame when illuminated by the sodium lamp should Stay the same, get darker, or lighter?
Physics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

Lighter

Explanation:

In practice, the lamp is powered by an AC voltage source which is connected in series with an inductive ballast in order to supply an approximately constant current to the lamp, rather than a constant voltage. This helps to provide a stable operation. The ballast is usually inductive rather than simply being resistive to maximize resistive losses.

As this lamp current tending to zero-current point and shadow cast by the sodium flame becoming lighter.  

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What is the relationship between the poles of a magnet? which direction does the magnet field move?
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3 years ago
Glycerin is poured into an open U-shaped tube until the height in both sides is 20cm. Ethyl alcohol is then poured into one arm
Liula [17]

Answer:

7.5 cm

Explanation:

In the figure we can see a sketch of the problem. We know that at the bottom of the U-shaped tube the pressure is equal in both branches. Defining \rho_A: Ethyl alcohol density and \rho_G: Glycerin density , we can write:

\rho_A\times g \times h_1 + \rho_G \times g \times h_2 = \rho_G \times g \times h_3

Simplifying:

\rho_A\times h_1 = \rho_G \times (h_3 - h_2) (1)

On the other hand:

h_1 + h_2 = \Delta h + h_3

Rearranging:

h_1 - \Delta h = h_3 - h_2 (2)

Replacing  (2) in (1):

\rho_A\times h_1 = \rho_G \times (h_1 - \Delta h)

Rearranging:

\frac{h_1 \times (\rho_A - \rho_G)}{- \rho_G} = \Delta h

Data:

h_1 = 20 cm; \rho_A = 0.789 \frac{g}{cm^3}; \rho_G = 1.26 \frac{g}{cm^3}

\frac{20 cm \times (0.789 - 1.26) \frac{g}{cm^3}}{- 1.26\frac{g}{cm^3}}  = \Delta h

7.5 cm =  \Delta h

7 0
3 years ago
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