All categories

3 years ago

Whcen the north pole is tilted toward the sun, which area has the fewest hours of daylight?.

1 answer:

8 0

When the north pole is tilted toward the sun, the southern hemisphere has the fewest hours of daylight due to winter season in it.

<h3>Which area has the fewest hours of daylight?</h3>

When the North Pole is tilted toward the sun, the Northern Hemisphere has the most hours of daylight while on the other hand, the Southern Hemisphere has the least hours of daylight.

So we can conclude that When the north pole is tilted toward the sun, the southern hemisphere has the fewest hours of daylight due to winter season in it.

Learn more about tilt here: brainly.com/question/818630

You might be interested in

PLease help with this this is pretty hard for me i kinda get it but not fully

vodka [1.7K]

Explanation:

Force = mass x acceleration

F= ma (formula)

15N = o.5kg x a

Divide both sides by o.5

a = 30 (greater acceleration)

15N = 4.5kg x a

Divide both sides by 4.5

a= 3.33 (great acceleration)

15N = 0.05kg x a

Divide both sides by 0.05

a = 300 (greatest acceleration)

5 0

2 years ago

Two timpani (tunable drums) are played at the same time. One is correctly tuned so that when it is struck, sound is produced tha

yKpoI14uk [10]

Answer:

Explanation:

Given

Wavelength of first timpani $\lambda _1=2.2\ m$

Frequency corresponding to this Wavelength

$f_1=\frac{v}{\lambda _1}$

where $v=velocity\ of\ sound (343 m/s)$

$f_1=\frac{343}{2.2}$

$f_1=155.9\ Hz$

Wavelength of Second timpani $\lambda _2=2.1\ m$

Frequency corresponding to this Wavelength

$f_2=\frac{v}{\lambda _2}$

$f_2=\frac{343}{2.1}=163.33\ Hz$

Beat frequency $=f_2-f_1$

Beat frequency $=163.33-155.9=7.43$

so approximately 7 beats per second

4 0

4 years ago

Two planets X and Y travel counterclockwise in circular orbits about a star, as seen in the figure. The radii of their orbits ar

Korvikt [17]

By 272.7 degrees angle has planet Y rotated through during this time.

<h3 /><h3>What is Kepler's 3rd law?</h3>

The cubes of the semi-major axes of the planets' orbits are precisely proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, as an orbiting planet's radius rises, so does the time of its orbit around the Sun.

Using Kepler's 3rd law, which says that the period of any planet's orbit squared is proportional to the radius of the orbit cubes, we can establish that

(period X / period Y)^2 = (radius X / radius Y)^3

(period X / period Y)^2 = 2^3 = 8

take sq root

period X / period Y = √8 = 2.82≅ 3

this means it takes planet X 2.82≅ 3 times longer to go through one orbit... so planet Y travels 2.82≅ 3 times as far (in its orbit...) as planet X!

This means...

planet Y travels 3 * 90.9 = 272.7 degrees

to learn more about Kepler's 3rd law go to - brainly.com/question/16705471

#SPJ4

7 0

2 years ago

(a) Determine the capacitance of a Teflon-filled parallel-plate capacitor having a plate area of 1.80 cm2 and a plate separation

icang [17]

Explanation:

(a) Given that,

Area of a parallel plate capacitor, $A=1.8\ cm^2=1.8\times 10^{-4}\ m^2$

The separation between the plates of a capacitor, $d=0.01\ mm = 10^{-5}\ m$

The dielectric constant of, k = 2.1

When a dielectric constant is inserted between parallel plate capacitor, the capacitance is given by :

$C=\dfrac{k\epsilon_o A}{d}$

Putting all the values we get :

$C=\dfrac{2.1\times 8.85\times 10^{-12}\times 1.8\times 10^{-4}}{0.01\times 10^{-3}}\\\\C=3.345\times 10^{-10}\ F\\\\C=334.5\ pF$

(b) We know that the Teflon has dielectric strength of 60 MV/m, $E=60\times 10^6\ V/m$

The voltage difference between the plates at this critical voltage is given by :

$V=Ed\\\\V=60\times 10^6\times 0.01\times 10^{-3} \\\\V=600\ V$

V = 0.6 kV

3 0

3 years ago

How does the today's model of the atom DIFFER from the Rutherford’s model? 25 Points

Yuliya22 [10]

Answer:

The Rutherford Model shows an atom with electrons orbiting a fixed, positively charged nucleus in set, predictable paths. The Bohr model shows electrons travel in defined circular orbits around the nucleus.

Explanation:

8 0

3 years ago

Read 2 more answers